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400    CHAPTER 17 GAS TURBINES




             giving

                                              q 45        s R
                                                  ¼ g 1                                  (17.49)
                                              c p T 1      s r
                Thus energy added per unit mass is,

                                             q in   1
                                                ¼      q 23 þ q 45                       (17.50)
                                            c p T 1  c p T 1

                                                                εg         s R
                                                ¼ g   s r ð1   εÞ   þ g 1
                                                                s R        s r
                                                                                         (17.51)
                                                                 εg   gs R
                                                ¼ 2g   s r ð1   εÞ
                                                                 s R   s r
                Differentiating with respect to s R .
                                               1  vq in  εg  g
                                                      ¼                                  (17.52)
                                              c p T 1 vs R  s 2  s r
                                                         R
                Considering now the work done per unit mass is

                                                                  s R
                                      w 34 ¼ c p ðT 3   T 4 Þ¼ c p T 1 g 1               (17.53)
                                                                  s r
                                                                   1

                                      w 56 ¼ c p ðT 5   T 6 Þ¼ c p T 1 g 1               (17.54)
                                                                  s R
                                       w 12 ¼ c p ðT 1   T 2 Þ¼ c p T 1 ðs r   1Þ        (17.55)
                Thus

                                    w           s R         1
                                        ¼ g 1       þ g 1        ðs r   1Þ               (17.56)
                                   c p T 1      s r         s R
                Hence
                                              1  vw      g    g
                                                     ¼     þ                             (17.57)
                                             c p T 1 vs R  s r  s 2 R
                Substituting in Eqn (17.39) gives

                                                    !
                                              εg   g       g   g
                                           h   2      ¼      þ  2
                                              s R  s r     s r  s R
             and rearranging, results in
                                                2     ðεh   1Þ
                                               s ¼ s r                                   (17.58)
                                                R
                                                      ðh   1Þ
                                                p ffiffiffiffiffi
                If ε ¼ 1 this equation reduces to s R ¼  s r i.e.
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