Page 422 - Advanced thermodynamics for engineers
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412    CHAPTER 17 GAS TURBINES




             Solution
                The values of (n   1)/n for the polytropic compression and expansion are
                for compression
                                   n   1    1    k   1      1
                                        ¼              ¼         ¼ 0:3175
                                     n    h NC    k   a  0:9   3:5
                for expansion

                                      n   1        k   1    0:9
                                           ¼ h NT         ¼    ¼ 0:225:
                                        n           k   g   4
                Under static conditions T 01 ¼ T 0a and p 01 ¼ p a so that, using the nomenclature of Fig. 17.23,

                                                    ðn 1Þ=n
                                         T 02  p 02
                                            ¼              and yields
                                         T 01  p 01
                                       T 02 ¼ 288   1:65 0:3175  ¼ 337:7K
                                       T 02   T 01 ¼ 337:7   288 ¼ 49:7K
                                       p 03  19:0
                                           ¼     ¼ 11:51
                                       p 02  1:65
                                             ðn 1Þ=n
                                         p 03                   0:3175
                               T 03 ¼ T 02         ¼ 337:7   11:51   ¼ 734 K
                                         p 02
                                       T 03   T 02 ¼ 734   337:7 ¼ 396:3K:

                The cold nozzle pressure ratio is
                                                p 02
                                                   ¼ r f ¼ 1:65
                                                p a
             and the critical pressure ratio for this nozzle is

                           p 02            1                    1
                               ¼                       ¼                 ¼ 1:965:
                            p c  h   1 k   1 ii k=ðk   1Þ  h  1  h 0:4 ii 3:5
                                       h
                                  1                       1
                                     h k þ 1                 0:95 2:4
                                      j
                Thus the cold nozzle is not choked, so that p 8 ¼ p a and the bypass thrust F b is given simply by
                                                 F b ¼ _ m b V 8
                The nozzle temperature drop, from Eqn (17.70),is
                                                                 !
                                                      1
                                                           k   1=k
                               T 02   T 8 ¼ h T 02 1
                                          j
                                                    P 02 =P a
                                                                  !
                                                           1
                                                               1=3:5
                                       ¼ 0:95   337:7 1             ¼ 42:8K:
                                                          1:65
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