Page 298 - Aerodynamics for Engineering Students
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280  Aerodynamics for Engineering Students

                   Example 6.1  In streamline airflow near the upper surface of an aeroplane wing the velocity
                   just outside the boundary layer changes from 257 km h-’  at a point A near the leading edge to
                   466 kmh-’  at a  point  B  to  the  rear  of  A. If  the temperature at A is 281 K  calculate the
                   temperature at B. Take 7 = 1.4. Find also the value of the local Mach number at the point B.
                                                                                       (LU)
                   Assume that the flow outside the boundary layer approximates closely to quasi-one-dimen-
                   sional, isentropic flow.
                   Then







                                     UA  = 72.4fi   and  TA = 8 + 273 = 281 K
                                     UA = 1215kmh-’






                                             1
                                     -_ - 1 + - [0.2122 - 0.385’1  = 0.979 = 1 - 0.021
                                     TB
                                     TA      5
                   Therefore
                                      TB = 0.979 x 281 = 275K = temperature at B
                                      UB = 72.4&%  = 1200 km h-’
                                     MB=-- 466  -0.386
                                          1200

                   Example 6.2  An aerofoil is tested in a high-speed wind tunnel at a Mach number of 0.7 and at
                   a point on the upper surface the pressure drop is found to be numerically equal to twice the
                   stagnation  pressure  of  the  undisturbed  stream. Calculate from  first principles the  Mach
                   number found just outside the boundary layer at the point concerned. Take y = 1.4.   (LU)
                   Let suffix 30 refer to the undisturbed stream. Then, from above,




                   with  = 1.4, this becomes
                                               5a2, + 2,  = 52 + 3
                   Dividing by 2,




                   but
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