Page 299 - Aerodynamics for Engineering Students
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Compressible flow  281

             with the data given,

                                        P  - 1 - 7Mk = 0.314
                                           =
                                        Pm
             and Eqn (i) gives






                                      M2 = 2.635 giving M  = 1.63


             6.2.2  The ratio of areas at different sections of the stream tube
                     in isentropic  flow
             It is necessary to introduce the mass flow (riz)  and the equation of continuity, Eqn
             (6.14). Thus riz = puA for the general section, i.e. without suffix. Introducing again
             the reservoir or stagnation conditions and using Eqn (6.1):


                                                                                (6.21)

               Now the energy equation (6.17) gives the pressure ratio (6.18) above, which when
             referred to the appropriate sections of flow is rearranged to






             Substituting d5 a0  and introducing both into Eqn (6.21), the equation of
                                for
             continuity gives


                                                                                (6.22)

               Now, if  the general section be  taken to be  the particular  section at the throat,
             where in general usage conditions are identified by an asterisk e), the equation of
             continuity (6.22) becomes



                                                                                (6.23)


             But from Eqn (6.18b) the ratio p*/po has the explicit value

                                        p*     + 1  -7/(7-1)
                                        Po -=  [TI
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