Page 50 - Aerodynamics for Engineering Students
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Basic concepts and definitions  33

                 A particular case is that when the known values of CM are those about the leading
               edge, namely CM~~. In this case u = 0 and therefore

                                                                                  (1.52)

               Taking this equation with the statement made earlier about the normal position of
               the aerodynamic centre implies that, for all aerofoils at low Mach numbers:

                                                                                  (1.53)



               Centre of pressure
               The  aerodynamic forces  on an  aerofoil  section  may  be  represented by  a  lift,  a
               drag,  and  a  pitching moment.  At  each value  of  the  lift  coefficient there will  be
               found to be  one particular  point  about which the pitching moment coefficient is
               zero, and the aerodynamic effects on the  aerofoil section may  be  represented by
               the lift and the  drag  alone acting at that  point.  This special point  is termed  the
               centre of pressure.
                 Whereas the aerodynamic centre is a fixed point that always lies within the profile
               of  a  normal  aerofoil  section, the  centre  of  pressure  moves  with  change  of  lift
               coefficient and is not necessarily within the aerofoil profile. Figure  1.11 shows the
               forces on the aerofoil regarded as either
               (a)  lift, drag and moment acting at the aerodynamic centre; or
               (b)  lift and drag only acting at the centre of pressure, a fraction kcp of the chord
                   behind the leading edge.
               Then, taking moments about the leading edge:

                      M~~=M~~-(Lco~a+Dsina)x*c=-(Lcosa+Dsin~)kcpc
               Dividing this by  pV2Sc, it becomes

                                                 XAC
                                                     =
                        CM, - ( CL cos Q + CD sin a) - - ( CL cos a + CD sin a)kcp
                                                   C
               giving
                                           XAC
                                     kcp = -           CMAC                       (1.54)
                                               -
                                            c    CLcosa+Cgsina











               Fig. 1.11  Determination of the centre of  pressure position
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