Page 515 - Aircraft Stuctures for Engineering Student
P. 515

496  Matrix methods of structural analysis

             displacements are related through a stzfjness matrix [K]. We shall see that, in general
                                            {F) = [KI{S)                        (12.1)

             where [K] is a symmetric matrix of the form



                                                                                (12.2)



              The element k, (that is the element located on row i and in columnj) is known as the
              stzfness  influence  coeficient  (note k, = kji). Once the stiffness matrix  [K] has been
              formed the complete solution to a problem follows from routine numerical calcula-
              tions that are carred out, in most practical cases, by computer.


                           :ness matrix for an elastic spring

             The formation of the stiffness matrix [K] is the most crucial step in the matrix solution
              of any structural problem. We shall show in the subsequent work how the stiffness
             matrix for a complete structure may be built up from a consideration of the stiffness
             of its individual elements. First, however, we shall investigate the formation of  [K]
             for a simple spring element which exhibits many of the characteristics of an actual
             structural member.
               The spring of stiffness k shown in Fig. 12.1 is aligned with the x axis and supports
             forces Fx,, and Fx,2 at its nodes  1 and 2 where the displacements  are u1 and u2. We
             build  up  the  stiffness matrix  for this  simple case  by  examining different  states  of
             nodal  displacement. First  we  assume  that node  2  is prevented  from moving  such
             that u1 = u1 and u2 = 0. Hence

                                             FYJ  = ku1
             and from equilibrium we see that

                                         Fx,2 = -Fx,l  = -kul                   (12.3)
             which indicates that FY,2 has become a reactive force in the opposite direction to F.Y,l.
             Secondly, we take the reverse case where u1 = 0 and u2 = u2 and obtain
                                                                                ( 12.4)
                                         FY,2 = kU2  = -&1










             Fig.  12.1  Determination of stiffness matrix for a single spring.
   510   511   512   513   514   515   516   517   518   519   520