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GRAPHICAL SOLUTION PROCEDURE  47


                                      Figure 2.9 Optimal Solution for the GulfGolf Problem

                                                 D


                                              600                10S + 9D = 7668



                                             Number of Deluxe Bags  400           Optimal Solution
                                                                   Maximum Profit Line





                                              250
                                              200





                                                                                                        S
                                                 0          200          400     550  600        800
                                                                  Number of Standard Bags





                                         The optimal values of the decision variables are the S and D values at the optimal
                                      solution. Depending on the accuracy of the graph, you may or may not be able to
                                      determine the exact S and D values. Referring to the graph in Figure 2.9, the best we
                                      can do is conclude that the optimal production combination consists of approxi-
                                      mately 550 standard bags (S) and approximately 250 deluxe bags (D).
                                         A closer inspection of Figures 2.5 and 2.8 shows that the optimal solution point is
                                      at the intersection of the cutting and dyeing and the finishing constraint lines. That
                                      is, the optimal solution point is on both the cutting and dyeing constraint line:


                                                                    0:7S þ 1D ¼ 630                     (2:7)

                                      and the finishing constraint line:


                                                                  1S þ 0:6667D ¼ 708                    (2:8)


                                      Thus, the optimal values of the decision variables S and D must satisfy both
                                      Equations (2.7) and (2.8) simultaneously. Using Equation (2.7) and solving for S
                                      gives:
                                                                    0:7S ¼ 630   1D
                                      or


                                                                   S ¼ 900   1:4286D                    (2:9)






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