Page 352 - Analog and Digital Filter Design
P. 352

Filter Integrated Circuits




                      number, The clock to sine wave frequency ratio in the examples shown in Figure
                      14.5 is 20: 1, so each clock cycle represents a phase change of  18". After the first
                      clock cycle is complete the output voltage should be Vo, = T.'-  V. cos( 18")  - P&,.
                      After subsequent clock cycles the output voltage should be  b,? V - Jr. cos(N
                                                                             =
                      x IS") - Vo,,,-,,. A table of normalized output voltage steps is given in Table 14.2,
                      by letting  V= I and  Voo = 0

                       Angle, Q degrees    Sinusoid Amplitude   Step n     Step Voltage,  Kos

                              0                0                  0           0
                             18                0.024772           1           0.048944
                             36                0.095492           2           0.14204
                             54                0.206107           3           0.270175
                             72                0.315492           4           0.420808
                             90                0.5                5           0.579 192
                            108                0.654508           6           0.729815
                            126                0.793893           7           0.85796
                            114                0.904508           8           0.951057
                            162                0.975528           9           1
                            180                1                 10           1

                Table 14.2
                Output Voltage Steps to Produce a Sinusoid

                      Only one resistor will  be connected to the positive supply after the first clock
                      cycle, so G,, = G1, where  G1 = UR1. Normalizing  the values of  V and R1 (let
                      them equal one), so that  G1 = 1, allows a value for G, to be calculated. After
                      one clock cycle:









                      This equation can be transposed to find G,:

                            G,  = GI/Vo,

                      Referring to Table 14.2 to find  Pb,:

                            G, = 1/0.04894 = 20.433.

                      Knowing G1 and G,.  the remaining conductance values can be found. In terms
                      of  a formula:
   347   348   349   350   351   352   353   354   355   356   357