Page 432 - Analysis and Design of Machine Elements
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Analysis and Design of Machine Elements
                   410
                          While for ordinary extension springs or compression springs,
                                     Gd
                               n =           max  ≥ 3
                                   8F   C 3
                                     max
                          Normally, the recommended number of active coils should be within the range of
                          3–15. The total number of coils should account for end coil configurations, which
                          can be found in Table 14.1. This influences overall spring flexibility.
                       5) Check rigidity, load, deflection, static and fatigue strength, stability of compression
                          spring and potential surging if required
                       6) Decide the dimension of springs
                          For a compression spring, closed and ground ends are usually a good choice; while for
                          an extension spring, a full end loop over the centre is preferred. A clearance between
                          coils    should be allowed to avoid coil-to-coil contact when a spring is at its maxi-
                               1
                          mum operating deflection. After calculation, it is required to check whether spring
                          variables satisfy installation requirements.
                       7) Produce working drawing for the spring


                       14.4.5  Design Cases


                       Example Problem 14.1
                       Design a cylindrical helical compression spring with a mean diameter of 18 mm. The
                       spring deflects 5 mm when the applied load varies from F  = 150 N to F  = 250 N.
                                                                        min          max
                       Loading is essentially static. The spring end is closed but not ground and both ends are
                       fixed.

                       Solution


                        Steps             Computation                          Results     Units

                        1. Select material,  Select oil tempered carbon steel for spring wire.  [  ] = 880  MPa
                        the diameter of   Select the diameter of spring wire as d = 3 mm.
                        spring wire and   From Figure 14.16, select    = 1150 MPa,
                        allowable stress                     e
                                             =   e   =(1277 ∼ 1916) MPa
                                           b
                                              0.6 ∼ 0.9
                                          Select    = 1600 MPa and from Table 14.3,
                                               b
                                          we have
                                          [  ]=0.55 ×    = 880 MPa
                                                     b
                        2. Select mean    The mean diameter of spring coil is D = 18 mm.
                        diameter for the
                        coil
                                             D   18
                        3. Compute spring  C =  =   = 6                        C = 6
                        index C              d    3
                        4. Compute the    From Eq. (14.11), we have            K = 1.2525
                                                                                 w
                        Wahl factor K         4C − 1  0.615  4 × 6 − 1  0.615
                                  w       K ≈       +     =        +
                                           w
                                              4C − 4   C    4 × 6 − 4  6
                                          = 1.2525
                                                                                       (continued)
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