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220   Applied Petroleum Geomechanics
























          Figure 6.19 Effective tangential stress and total radial stress (mud pressure) along the
          wellbore circumference in a horizontal well drilled in the minimum horizontal stress
          direction and located in the reserve faulting stress regime.

          generate horizontal fractures because a much larger tensile stress (absolute
          value) is created at the wellbore wall (this can be found by comparing Eq.
          (6.61) to Eq. (6.66)). It may imply that for hydraulic fracturing operations in
          a vertical well, the vertical fractures may be initiated first; these vertical
          fractures will rotate and eventually develop into horizontal fractures after
          penetrating through the near-wellbore zone into the undisturbed formation
          because s V is the minimum in situ stress.
             Because the maximum horizontal stress is the largest in situ stress in the
          reverse faulting stress regime, the tensile fractures (horizontal ones) will
          initiate at the side of the horizontal well (as shown in Figs. 6.18 and 6.19).
          However, when the horizontal wellbore is not aligned with a principal
          horizontal stress direction, the shear stress at the wellbore wall is not zero.
          The borehole wall subjected to the maximum tension is at an angle (g)to
          the borehole axis, and en echelon fractures are generated, as shown in
          Fig. 6.14B. At the wellbore wall the effective principal tensile stress is equal
          to the minimum effective principal stress and can be obtained by the
          following equations:
                                          s ffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffi
                                                      2
                                  0
                                s þ s 0       s   s 0 q
                                               0
                                  z
                                               z
                         s 0  ¼       q                þ s qz         (6.67)
                           tmax
                                   2            2

                                     1    1   2s qz
                                 g ¼ tan                              (6.68)
                                     2      s   s 0 q
                                             0
                                             z
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