Page 27 - Applied Process Design For Chemical And Petrochemical Plants Volume II
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16                       Applied Process Design for Chemical and Petrochemical Plants


          For binary mixtures [147]:                            where Xi = mols of a component i in vapor plus mols of same
            1. Set the temperature and pressure of the flash chamber.    component in liquid, divided by total mols of feed
            2. Make a material balance on a single component.            (both liquid and vapor)
                                                                        = total mol fraction, regardless of whether compo-
              FtXi = Vyi + Ixi                         (8-21)            nent is in liquid or vapor.
            3. Knowing F,  calculate amount and composition of V   FXi=vyi+LXi                              (8-23H)
              and L.
              Ft = F + V,  = mols of feed plus mols of noncondensable gases   xi = yi/&
              From Henry’s Law:                                 yi=V+L/&                                    (8-231)

              FtXfi = Vtyi + L (yi/Ki)                 (8 - 22)
              Vt = V + V,  = mols of vapor formed plus mols non-                                            (8  - 235)
              condensed gases

              &=&xi                                             2yi = 1.0
            4. Ft = V, + L                            (8 - 22A)
                                                                                                            (8- 23K)
                                                       (8-23)



                                                                  To calculate, V, L, yi’s, and xi’s:
              Yi       x,                             (8 - 23A)
                                                                  1. Assume: V
                                                                  2. Calculate: L = F - V
                                                                  3. Calculate: L/V
              After calculating  V,  calculate the xi’s and yi’s:
                                                                  4. Look up q’s at temperature and total pressure of sys-
                                                                    tem
                     Fx,
              yiv = -                                 (8 - 23B)   5. Substitute in:
                       L
                   1+-
                      KiV
              Then,                                                                                          (8 - 24)
                   (7)
              y. =-                                   (8 - 23C)   6. If an equality is obtained from:
                  l+-  L                                            Vcdc = Vassmed  the amount of vapor was satisfactory
                     KiV                                                   as assumed.
            Calculate each y; after calculating the yi’s, calculate xi’s
                                                                                                   F1(,
                                                                                                             (8 - 25)
          as follows:                                            V=-   -1   L   +-+-  Fx,   Fx,   +*.e.  -
                                                                                 L
                                                                                         L
                                                                                                     L
                                                                    1+-      l+-     l+-          1+-
                                                        (8-8)          K1V     K2V      K3V         KiV
                                                      (8-23D)     7. vyi =-   Fx;                           (8 - 23B)
                                                                         1+-  L
                                                                            KiV
                                                        (8- 8)
                                                                                                            (8  - 23C)
                                                      (8 - 23E)
                                                      (8 - 23F)
                                                      (8 - 23G)   8. Calculate each yi as in  (7) above, then  the xi’s  are
                                                                    determined
           Yi - Pi
           xi  Jd
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