Page 224 - Applied statistics and probability for engineers
P. 224

202     Chapter 6/Descriptive Statistics


                                                                                        x
                                   some of the deviations x i −  will be. Because the deviations x i −  always sum to zero, we
                                                         x
                                   must use a measure of variability that changes the negative deviations to non-negative quanti-
                                   ties. Squaring the deviations is the approach used in the sample variance. Consequently, if
                                   2
                                                                                       2
                                   s  is small, there is relatively little variability in the data, but if s  is large, the variability is
                                   relatively large.
               Example 6-2     Sample Variance  Table 6-1 displays the quantities needed for calculating the sample variance
                               and sample standard deviation for the pull-off force data. These data are plotted in Fig. 6-2. The
                           2
               numerator of s  is
                                                       8
                                                       ∑ ( x i − ) = 1 60.
                                                               2
                                                             x
                                                      i = 1
                                   5    6-1   Calculation of Terms for the Sample Variance and Sample Standard Deviation
                                    i              x i              x i −  x         (x i −  ) x  2
                                    1             12.6              –0.4               0.16
                                    2             12.9              –0.1               0.01
                                    3             13.4               0.4               0.16
                                    4             12.3              –0.7               0.49
                                    5             13.6               0.6               0.36
                                    6             13.5               0.5               0.25
                                    7             12.6              –0.4               0.16
                                    8             13.1               0.1               0.01
                                                 104.0               0.0               1.60


                                                  x
                                   12            13             14             15
                                             x 2      x 8


                                              x 1    x 3

                                              x 7     x 6

                                            x 4        x 5
                                   FIGURE 6-2  How the sample variance measures variability through the deviations x i − .
                                                                                                         x
               so the sample variance is
                                                    .
                                                          .
                                                   1 60  1 60               2
                                                                .
                                               s =     =     =  0 2286 (pounds )
                                                2
                                                    −
                                                   8 1    7
               and the sample standard deviation is
                                                   s =  0 .2286  = .48 pounds
                                                               0
                                   Computation of s  2
                                                    2
                                   The computation of s  requires calculation of x, n subtractions, and n squaring and adding
                                                                                     x
                                   operations. If the original observations or the deviations x i −  are not integers, the devia-
                                           x
                                   tions x i −  may be tedious to work with, and several decimals may have to be carried
   219   220   221   222   223   224   225   226   227   228   229