Page 226 - Arrow Pushing in Inorganic Chemistry A Logical Approach to the Chemistry of the Main Group Elements
P. 226

GROUP 16 ELEMENTS: THE CHALCOGENS
                206
                  In acidic solution, hydrogen peroxide is a powerful oxidizing agent (see Table 1.5,
                Section 1.5). The oxidation of iodide to iodine by acidified hydrogen peroxide is a good
                example for our purpose:

                                        −     +
                                     2I + 2H + H O → I + 2H O                       (6.8)
                                                   2  2  2     2
                To form an I–I bond, we need to convert one of the iodides to an electrophile. This is most
                                   −
                simply done by having I attack protonated H O :
                                                    2
                                                       2
                                    −
                                     I         H          I       H
                                         O   O +           O +  O                   (6.9)

                                       H       H         H        H
                A second iodide ion then attacks the hypoiodous acid (HOI, a weak acid with a pK of
                                                                                    a
                about 11) produced, yielding molecular iodine:
                                      −
                                      I   I       +              H
                                                 H
                                            O          I   I +  O                  (6.10)
                                          H                      H

                  In neutral or slightly alkaline solution, on the other hand, iodide promotes a different
                reaction, namely, the catalytic decomposition of hydrogen peroxide:

                                          2H O → 2H O + O                          (6.11)
                                             2  2     2     2
                The first step of the mechanism is still the same as in the above reaction, namely, the pro-
                duction of hypoiodous acid as an intermediate:

                                 −          H        I
                                 I                        − H O   I
                                                             2
                                      O   O            O             −
                                                                    O              (6.12)
                                    H                H    −
                                                          OH

                The hypoiodite anion, acting as a nucleophile, could then attack H O to produce the un-
                                                                     2
                                                                       2
                stable intermediate HOOI:
                                  I  −
                                     O         H        I
                                                                   −
                                         O   O            O   O +  OH              (6.13)
                                       H                        H
                                                                                      −
                Hydroxide anion-promoted E2 elimination then produces O and regenerates the I
                                                                  2
                catalyst, as follows:
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