Page 232 - Arrow Pushing in Inorganic Chemistry A Logical Approach to the Chemistry of the Main Group Elements
P. 232

GROUP 16 ELEMENTS: THE CHALCOGENS
                212
                  If you don’t want to see a triphenylphosphine attack a negatively charged sulfur, you
                could isomerize this intermediate to a cyclic form with no formal charges. Its breakdown
                to two molecules of Ph PS would then happen as follows:
                                  3
                                   +                           S
                                Ph P       S −           Ph P
                                                           3
                                  3
                                        S                      S
                                                     +               +
                             Ph P
                        S      3                S    PPh 3        Ph P  −     −   +
                 Ph P                     Ph P    −                 3   S  +  S   PPh 3
                   3
                                            3
                        S                       S
                                                                                   (6.38)
                  In the same manner, aqueous potassium cyanide breaks down the S ring to thiocyanate
                                                                       8
                    −
                (NCS ):
                                                   −        −
                                          S + 8CN → 8NCS                           (6.39)
                                           8
                The first few steps proceed exactly as for the Ph P reaction, that is, reaction 6.35, until we
                                                      3
                arrive at the following intermediate:











                Once again, the puzzle consists of cleaving the last S–S bond and producing the last thio-
                cyanate ions. You probably don’t want a cyanide ion attacking a negatively charged sulfur.
                The negative charge on the terminal sulfur, however, is easily neutralized by protonation,
                paving the way for the final S–S bond cleavage, as shown below:


                      O
                  H       H
                             −             H                             H
                   −         CN                                               −
                   S   S                     S   S            N   C    S   +  S    C   N
                               −       −
                          C   − OH      C           C
                                     N
                            N                         N
                                             −
                                           HO
                                                 H
                                                    − H O              −
                                                       2
                                      N    C   S              N    C   S
                                                                                   (6.40)
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