Page 236 - Arrow Pushing in Inorganic Chemistry A Logical Approach to the Chemistry of the Main Group Elements
P. 236

GROUP 16 ELEMENTS: THE CHALCOGENS
                216

                  REVIEW PROBLEM 6.5
                  Unlike SO , which is a gas under ordinary conditions, SeO is a white polymeric
                           2                                       2
                  solid:


                                            O   +  O   +  O
                                               Se     Se
                                                 −      −    n
                                               O      O



                  It sublimes, however, at 588 K to yield a gas consisting of discrete SeO molecules.
                                                                           2
                  Solid SeO reacts (i) with water to yield selenous acid, H SeO , an analog of
                                                                        3
                           2
                                                                    2
                  sulfurous acid, and (ii) with aqueous sodium hydroxide to yield sodium selenite,
                  Na SeO . Write balanced equations for the two reactions and use arrow pushing to
                    2    3
                  account for the products H SeO and Na SeO .
                                       2    3      2   3

                  With an intermediate valence of 4 and a sulfur oxidation state of +4, SO can act
                                                                                2
                as both a reducing agent and an oxidizing agent. The reducing properties, however, are
                more commonly of interest. Thus, aqueous SO (or H SO ) reduces both bromine and
                                                      2
                                                                3
                                                            2
                iodine.
                                             −                    −
                                    X + HSO   + H O → 2HX + HSO                    (6.50)
                                     2      3     2               4
                Although the reaction doesn’t look too complicated, a plausible mechanism may not be
                readily apparent. The fact that sulfur is being oxidized (i.e., acts as an electron donor) while
                molecular halogen is being reduced suggests that a nucleophilic attack by the hydrogensul-
                        −
                fite (HSO )sulfuronX may be worth considering:
                       3
                                    2
                                   HO                 −          OH
                                     +  S   X   X   − X    X  2+ S
                                  −                                 −              (6.51)
                                    O                             O
                                      O                         O  −
                                       −

                The product thus obtained is then hydrolyzed to hydrogensulfate:


                                   H
                             OH          −    HO       H      +   HO
                         2+           − X         2+      − 2 H       2+  −
                       X   S     O               S   O +             S   O         (6.52)
                               −             −                   −
                             O     H          O        H          O
                            O  −              −  O                 −  O
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