Page 324 - Arrow Pushing in Inorganic Chemistry A Logical Approach to the Chemistry of the Main Group Elements
P. 324

THE NOBLE GASES
                304
                As in many ligand exchange reactions, the mechanism involves the formation of a bridged
                intermediate, in this case involving a P–O–Xe bridge:
                                 F
                                   +   −
                                  P   O     F                    F
                                                               F
                                F       F       F                  −   F
                                 F          Xe                   Xe                (8.11)
                                        F       F          +   F      F
                                            F           F   P    F
                                                               F
                                                             F
                A fluoride migration may then take place. A second fluoride migration, concomitant with
                P–O bond cleavage, may then provide a possible route to the final products:
                                                                 F
                                           F                  F
                                         F
                                             −   F                  F
                                        O   Xe              O   Xe
                                     +           F
                                  F   P  F  F          F  P    F   F
                                                              F
                                         F             F
                                       F                  F                        (8.12)
                                                                        −
                                     F   F               F            O
                            F     O  Xe              F             F      F
                                          F              P   F  +     Xe
                               P                                       +
                            F       F                 F           F       F
                                  F    F                 F
                              F


                  REVIEW PROBLEM 8.3
                                          −
                  XeF reacts with nitrate (NO ) to give nitryl fluoride (NO F) and XeOF :
                     6                   3                       2          4
                                              −                   −
                                    XeF + NO    → NO F + XeOF + F
                                       6     3       2        4
                  Suggest a mechanism.



                                             +
                8.3  XENON FLUORIDES AS F DONORS AND OXIDANTS
                A perusal of standard reduction potentials (see, e.g., Table 1.6) immediately shows that
                XeF is a powerful oxidant. Thus, it readily oxidizes HCl to Cl :
                   2                                              2
                                      XeF + 2HCl → Xe + HF + Cl 2                  (8.13)
                                          2
                Given that HF is a product and that it has a very high bond dissociation energy (BDE
                569 kJ/mol), it’s reasonable to start by protonating one of fluorines of XeF .
                                                                           2
                                                                     H
                                                                  +        −
                                           H   CI                                  (8.14)
                           F   Xe   F                     F   Xe   F   + CI
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