Page 40 - Battery Reference Book
P. 40

Effect of sulphuric acid concentration on e.m.f.  in the lead-acid  battery  1/25

       electrons involved in the net chemical reaction, T  the         (3
       temperature in kelvins, and R  the gas constant (8.312   = 2 x 0.029 57 log
       international ,joules).
        By definitison, apbso4 = aH20 = apb  = apb02  = 1.   = 0.059 15 log (E)

                                           (1.70)         = 0.0169 V at 25°C
                                                   or, in general,
       at 25°C                                              2 x 8.312 x  (273 + T) x 2.303log(a,,/u,,)
                                                   E,,  -E,,  =
              8.312 (273 + 25) x 2.203                                 2 x 96500
       E=EO-
                   2 x 96500                              = 0.000 1984(273 + T)log(a,,/a,)
        = Eo - 0.029 57 log (7)                    where  E,,  is  the  e.m.f.  at  T"C when  the  acid  has
                          1
                                           (1.71)   activity acl at the start of discharge, E,,  is the e.m.f. at
                        H2S04                      T"C when acid has activity a,, at the end of discharge,
                                                   and T is the cell temperature in "C. That is,
       Consider the previously discussed case of a lead-acid
       battery at the start and the end of discharge. At the start
       of  discharge the  electrolyte contains 29%  by  weight
       of  sdphuric  acid,  i.e.  molality = 4.17  and  activity
       coefficient = 0.202  (Table 1.3). Therefore,  the  activ-   To ascertain  the value of  the standard potential Eo
       ity  is  0.202 x 4.17 = 0.842.  Similarly, at the  end  of
       discharge,  the  acid  strength  is  21%  by  weight,  i.e.   According to the literature, the e.m.f. of a cell contain-
       m = 2.71 and y  = 0.161, i.e. a = 0.436.    ing 21% by weight (2.71 molal) sulphuric acid at 15°C
        If the cell potentials at the start and end of discharge   is 2.0100V.
       are respectively by  E29  and Ezl, then                  2.303 x 8.312 x 288   1
                                                         E=EO-     2 x 96500
                           1
       E29  = Eo - 0.029 57 log   -
                        ((0.842)')                        = Eo -  0.02856 x log (-)  1
          = Eo - 0.004 40 V                                                (0.436)'
                                                                             1
                                                                          -
       and                                              Eo = E + 0.02856 x log  ( (0.436y )
               0.029 57 log (-)  1                        = 2.0100 + 0.02856 = 2.03059V
       E21  =EO-
                         (0.436)2
                                                   E29(25"C)  = 2.030 59 - 0.00440 = 2.0262 V
          =Eo - 0.021 32V
                                                   and
       Therefore  the  potential  decrease  (E29 - E211  during   E21 (25°C) = 2.03059 - 0.021 32 = 2.0093 V
       discharge is given by
                                                   These  equations  can  be  used  to  calculate  the  effect
       E29  - E21  = -.0.00440 + 0.021 52V         of  sulphuric acid concentration (expressed as activity)
              = 0.0169V at 25°C                    and  cell  temperature  on  cell  e.m.f.  If,  for  example,
                                                   the  electrolyte  consists  of  29%  by  weight  sulpharic
       Alternatively                               acid at the start of discharge (i.e. activity a29 = 0.842)
                                                   decreasing to 21% by weight sulphuric acid @e. activ-
                        (2)                        ity a21  = 0.436) at the end of discharge, and if the tem-
      E29 = Eo - 0.029 57 log                      perature at the start of discharge, TI, is 15°C increasing
                        M                          to 40"C(TF) during discharge, then from Equation 1.71
      E21  = Eo - 0.029 57 log                     E29  = Eo -  8.312 x  (273 + 15) x 2.303  log (&)
                                                                 2 x 96500
       where E29 is c.he  cell e.m.f. at 25°C when the sulphuric   and
       acid  concentration  is  29%  by  weight,  i.e.  activity   8.312 x  (273 + 40) x  2.303
       a29 = 0.842, and  E21  is the cell e.m.f. at 25°C when   E21  = Eo -
      the sulphuric acid concentration is 21% by weight, i.e.    2 x 96500
       activity ~2~  = 0.436.                      If  Eo = 2.0359 V,
                                                   E29  = 2.0263 V
                                                   E21  = 2.0082V
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