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42    Chapter  Two



                                    m 2
                                          f a (t)
                                               x(t)
                                          f a (t)

                                    m 1                  x 2 (t)

                                               x (t)
                                                1
                              k             c




               FIGURE 2.5  Schematic representation of a mass–spring–damper system with
               a second mass connected to it by an actuator; m  and m  are the masses,
                                                    1     2
               k is the spring constant, c is the damping constant, f (t) and x(t) are the
                                                       a
               time-dependent actuator force and length, respectively, and  x (t) and x (t)
                                                             1      2
               are the time-varying positions of the masses with respect to the solid
               body.

               the input variable q(t) should be integrated over time to obtain a linear
               relation with the output variable x(t) as follows:

                                            ∫
                                             t
                                     xt () =  K q t ()              (2.26)
                                            0
               The resulting mechanical subsystem is still one-dimensional, but now
               has two translational degrees of freedom, giving rise to two position
               signals: positions x (t) and x (t) with respect to the solid body of the
                                1      2
               masses m  (e.g., tractor body) and m  (e.g., implement), respectively.
                       1                      2
                   The equation of motion for the first mass has been derived previ-
               ously [Eq. (2.10)]:
                                      2
                                     dx t()   dx t ()
                                                1
                                        1
                            − ft()  = m    + c     + kx t ()        (2.27)
                              a     1    2             1
                                       dt      dt
               where  f (t) is the time-dependent actuator force acting on the first
                      a
               mass m .
                      1
                   The equation of motion for the second mass m  can be derived
                                                           2
               from Newton’s second law:
                                             2
                                            dx t()
                                    ft() =  m  2                    (2.28)
                                     a     2   2
                                             dt
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