Page 199 - Calculus Demystified

CHAPTER 6
186
y Transcendental Functions
y = Tan x

x

Fig. 6.19

y

_
1
y = Tan x

x

Fig. 6.20

SOLUTION
We have

π
−1
Tan 1 = ,
4
√ π
Tan −1 1/ 3 = ,
6
√ π
Tan −1 (− 3) =− .
3