Page 323 - Calculus Demystified

310
8. The work performed is Solutions to Exercises
100

2
W = [3x + 4x + 6] dx
3

100
2
3
= x + 2x + 6x
3
= (1000000 + 20000 + 600) − (27 + 18 + 18)
= 1020547 ft lbs.

π
2
9. (a) 1 +[cos x] dx
0
8
#
(b) 1 +[(2/3)x −1/3 2
] dx
1
π/2 #

2
(c) 1 +[− sin y] dy
0

4
2
(d) 1 +[2x] dx
1
1 5
2
10. (a) sin xdx
3 2
π/4
1
(b) tan xdx
π/4 0
2
1 x
(c) dx
4 −2 x + 1
1 2π sin x
(d) dx
3π −π 2 + cos x
6
2 2
11. (a) e −(2j/3) ·
3
j=1
10
2
(b) sin(e −2+2j/5 ) ·
5
j=1
5
2 2
(c) cos(−2 + 2j/5) ·
5
j=1
12 j/3
e 1
(d) ·
2 + sin(j/3) 3
j=1