Page 83 - Cam Design Handbook
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THB3  8/15/03  12:58 PM  Page 71

                                     MODIFIED CAM CURVES                    71

                                         Skewed displacement
                                             Symmetrical displacement



                     Displacement  acceleration  Transition  h 2  h

                          point
                                          h/2
                                                     h 1
                                                b  Cam angle q
                             b 1           b 2
                              b /2        b /2
                                 b
                                   1                   Symmetrical acceleration
                                                       Skewed acceleration
                  A 1 Asym

                                                    A 2
                          Cam angle q                 Asym
                                          2
                 FIGURE 3.7.  Skewed modified trapezoidal curve.




            and
                                              p
                                         b =    b
                                          2
                                            1+ p
                                                                          (3.11)
                                              p
                                         h 2  =  h.
                                            1+ P
            The relationship between the skewed and corresponding symmetrical acceleration, since
            the maximum velocity is the same in both skewed and symmetric cases, is:
                                      2b a =  a sym b =  V max
                                        11
                                                b
                                      \  a =  a
                                          1  sym
                                               2b
                                                 1
            Thus using Eq. (3.10)
                                          Ê 1+  p ˆ
                                       a =      a .                       (3.12)
                                          Ë  2 p ¯
                                        1        sym
            Similarly
                                           Ê 1+  p ˆ
                                       a =      a .                       (3.13)
                                        2  Ë  2  ¯  sym
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