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9.12.  COOLING TOWERS



              EXAMPLE 9.11                                     or
              Sizing  of  :a  Cooliing  Tower:  Number  of  Transfer  Units  and
              Height of ]Packing                                  HTU = 5.51(L/G)0.s9.
           Water  is  to  be  cooled from  110 to  75°F  by  contact with  air  that
           enters countercurrently at 90°F with a dewpoint of  60°F. The data of   Tower height:
           London et al.  i(1940)  of  Figure 9.16 for height of  transfer unit are
           applicable.  Calculations  will  be  made  for  two  values  of  the   Z  = (HTU)(NTU).
           coefficient ratio  k,/k,,  namely, 25  and  ~0  Btu/("F)  (lb dry air), of
           Eq.  (9.31). Tkx effect of  the ratio of  liquid to gas rates, L/G, will   For several values of L/G:
           be explored.
                                                                          Ll G     0.6   I   1.4   1.7
                                                                          HTU (ft)   4.08  5.51  6.72  7.54

                                                               Evaluation  of  interfacial  temp  and  the  WTU  for  L/G = 1 with
                                                               kJk,  = 25:
                                                                             T    h     T,   l/&-b)
                                                                            78.5   30.5   78.099   0.0864
                                                                            89   41    88.517   0.0709
                                                                            96   48    95.400   0.0575
                                                                            106.5   58.5   105.581   0.0385
                                                                                             -
                                                                                             0.2533
                         Ts2 = 90     T,  = 75                    .'. NTU  (110 - 75(0.2533)/4 = 2.217.
                         H  = o.ola
                         h  =27                                   For other values of  L/G:
              The  maximum  allowable  L/G  corresponds  to  equilibrium               1/(k - h)
           between exit air and entering water at 110. The saturation enthalpy
           at 110°F is 92, so that Eq. (9.30) becomes                    T   h  L/G=0.6   1   1.
                                                                        78.5  30.5  0.0751  0.0864  0.0943  0.1043
                      '92 - 27  = 1.857.                                89   41   0.0518  0.0709  0.1167  0.2200
                 max  110-75                                            96   48   0.0398  0.0575  0.1089  0.3120
                                                                       106.5  58.5  0.0265   0.0385  0.0724  0.1987
                                                                                --____
           The several trials will be made at L/G = (0.6,  1.0, 1.4, 1.7).      0.1933   0.2533  0.3923  0.8350
              The applicable equations with numerical substitutions are listed   NTU +   1.691   2.217   3.433   7.306
           here and incorporated in the computer program for solution of  this
           problem [Eqs. 1(9.30)-(9.33)]  :                   With km/kh + m:
               h = 27 + (L/G)(T - 75),
              h3 = h + zqa - 75),                                                                  ~   ~~
              h, = 0.24T + (18/29)(0.45T + 1100)P,/(l-  PSI,          T   h   L/G=O.6   1    1.4    a .7
              P, = exp[1:1.9176 - 7173.9/(q + 389.5)].               78.5  30.5  0.0725   0.0807   0.90   0.1006
                                                                     89   41   0.0494   0.0683   0.1107   0.2070
           When km/kh+ 30,  T, in Eq. (9.33) is replaced by  T.      96   48   0.0376   0.0549   0.1020   0.2854
              The  four temperatures  at which the  integrands  are  evaluated   106.5  106.5  0.0248   0.0361   0.0663   0.1778
                                                                             -___--
           for  the  Chebyshev  integration  are  found  with  Eq.  (9.34)  and   0.1844   0.2400   0.3700   0.7708
           tabulated in the calculation summary following.           NTU +    1.613   2.100   3.238   6.745
              Equations (9.30) and (9.31) are solved simultaneously for h and   2-   6.58   11.57   21.76   50.86
           h,  with  the  aid  of  the  Newton-Raphson  method  as  used  in  the
           computer program; the integrands are evaluated and the integration
           are completed with Eq.  (9.35).
              The number of  transfer units is sensitive to the value of  L/G,
           but the effect of  kJk,  is more modest, at least over the high range
           used; data for this ratio do not  appear to be prominently recorded.
           Figure 9.16 shows a wide range of  heights of  transfer units for the
           different kinds  of  packings,  here  characterized  by  the  surface  ad
           (sqft/cuft)  and substantial variation with L/G. The last line of  the
           cdculation summary shows variation of  the tower height with L/G.
              Data of  Lmdon et al. (1940) of  Figure 9.16:
              (G/L)(HTU) = 5.51(G/L)0.41
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