Page 337 - Compression Machinery for Oil and Gas
P. 337

322 SECTION    II Types of Equipment




                                                Breakdown
                                                  torque
                               Locked rotor torque
                                                 (pullout)
                                (starting torque)   C
                      Percent of full-load torque  100  A  B  (pull-in)  D
                        200
                                   Pull-up torque




                                           Full-load torque
                                                        Stable operating
                            Load torque-speed curve
                                                        point
                                           No-load speed
                                                          E
                         0
                          0               50            100
                                Percent of synchronous speed
            FIG. 7.11 Stable operating point.

               From Fig. 7.11, the motor would accelerate the load successfully since the
            motor torque is greater than the load torque up to the operating point. If load
            torque at the operating point increases, the motor will slow down. As it slows
            down, at lower speed, the motor torque increases and catches up with the
            increased load torque. The motor operation is stable.
               From Fig. 7.12, the motor would also accelerate the load successfully since
            the motor torque is greater than the load torque up to the operating point. If load
            torque at the operating point increases, the motor will slow down. As it slows
            down, at lower speed, the motor torque decreases so the motor slows down fur-
            ther. Eventually, the motor would stall. The motor operation is unstable.
               For a given speed, the motor torque varies at the square of voltage. This is
            important during motor start. When motor starts direct on line, the starting cur-
            rent is much larger than the full load current (e.g., 600% of the full load current)
            and causes the voltage drop at the motor terminal. At the moment when the
            motor starts from the locked rotor condition, the voltage at the motor terminal
            is typically between 80% and 90% of the rated voltage. As the motor acceler-
            ates, the motor current is reducing from the locked rotor current to the full load
            current and the motor terminal voltage recovers from the initial drop to a value
            approximately equal or close to the full-rated motor voltage. So if for example,
            initially, the voltage drops to 80% of the rated voltage, the motor starting torque
            would drop to 64% of the theoretical starting torque if starting voltage was equal
            to 100% of the full voltage. As the voltage recovers from the initial drop, the
            torque recovers too. Between the initial voltage drop at the motor terminals
            and the full motor voltage, there is a family of torque-speed characteristics,
            and the actual motor torque will be a point on a corresponding torque-speed
   332   333   334   335   336   337   338   339   340   341   342