Page 219 - Design and Operation of Heat Exchangers and their Networks
P. 219

208   Design and operation of heat exchangers and their networks


                                                      4 2
                       ρ ¼ 905:03 0:62602t +3:8112 10 t kg=m  3    (5.82)
                        oil
                                                       3 2
                       c p,oil ¼ 1835:4+ 3:5465t +4:4988 10 t J=kgK  (5.83)
                                                  5
                           λ oil ¼ 0:14494 8:8455 10 t W=mK        (5.84)
                                       2            4 2           6 3
              μ ¼ exp 0:1743 8:9038 10 t +6:1253 10 t  2:0359 10 t   sPa
               oil
                                                                    (5.85)
                Let the assumed oil outlet temperature and the wall temperature at the
             tube outside be its specified value, t s,m ¼t s,w ¼63°C, which yields
                                3
                   ρ ¼ 867:1kg=m ,c p,s ¼ 2076:7J=kgK,λ s ¼ 0:13937 W=mK,
                    s
                           μ ¼ 0:029806 sPa, Pr s ¼ Pr s,w ¼ 444:14
                            s
              (2)  Calculation of geometric parameters
             Eliminating the shell-to-tube bundle clearance δ st in Eq. (5.5) with
             Eq. (5.6), we obtain the tube bundle outer tube limit diameter:

                                ð
                                          ð
                 d otl ¼ d s  0:008ð  Þ= 1+ 0:01Þ ¼ 0:336 0:008Þ=1:01 ¼ 0:3248 m
                The diameter of the circle through the centers of the outermost tubes is
             given by Eq. (5.12):
                         d ctl ¼ d otl  d o ¼ 0:3248 0:019 ¼ 0:3058 m
                For the tube bundle with 45degrees rotated square arrangement, the
             longitudinal tube pitch
                                 p ffiffiffi      p ffiffiffi
                            s l ¼ s= 2 ¼ 0:025= 2 ¼ 0:01768 m
             the transverse tube pitch
                                p ffiffiffi  p ffiffiffi
                            s t ¼ 2s ¼ 2 0:025 ¼ 0:03536 m
             the diagonal tube pitch
                                    s d ¼ s ¼ 0:025 m
             the minimum transverse tube pitch


                                2 1=2                             2 1=2
                s l,min ¼ 0:52s t d o + d  ¼ 0:5  2 0:03536 0:019 + 0:019
                                o
                    ¼ 0:02064 m
             Because s l <s l,min , the effective transverse tube pitch is given by
                                    ∗
                                    s t ¼ s d ¼ 0:025 m
                The number of tubes N t is calculated by Eq. (5.11) with K¼0.156 and
             n¼2.291 taken from Table 5.1:
                                n                            2:291
                                                ð
               N t ¼ round Kd otl =d o Þ½  ð  Š ¼ round 0:156  0:32475=0:019Þ  ¼ 104
             The number of tubes per pass is
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