Page 221 - Design and Operation of Heat Exchangers and their Networks
P. 221

210   Design and operation of heat exchangers and their networks



                                           2:131
                          θ ds
                 A sb ¼ 1     πd s δ sb =2 ¼ 1    π  0:336 0:0044=2
                          2π                2π
                    ¼ 0:00155 m 2
                The baffle hole-to-tube leakage area can be calculated with Eq. (5.29):
                  π         2   2
              A bt ¼  ð d o + δ bt Þ  d N t 1 F w Þ
                                   ð
                                o
                  4
                  π               2      2                             2
                 ¼   ð 0:019 + 0:0008Þ  0:019  104  1 0:1782ð  Þ ¼ 0:002084m
                  4
                The shell-to-tube bundle bypass area is evaluated with Eq. (5.30):
                             ∗                                        2
              A bp ¼ l bc δ st + N tp δ tp ¼ 0:279  0:01125 + 2 0:0095ð  Þ ¼ 0:008439 m
                The leakage area ratios used for correction of the effects of tube-
             to-baffle and baffle-to-shell leakages are defined by Eqs. (5.58), (5.59):


                        ð
                 r s ¼ A sb = A sb + A bt Þ ¼ 0:00155= 0:00155 + 0:002084ð  Þ ¼ 0:4265
                     ð
                 r lm ¼ A sb + A bt Þ=A sc ¼ 0:00155 + 0:002084ð  Þ=0:03209 ¼ 0:1132
                The bypass area ratio and the ratio for correction of the effects of bundle
             and pass partition bypasses are defined by Eqs. (5.64), (5.65), respectively:

                         r b ¼ A bp =A sc ¼ 0:008439=0:03209 ¼ 0:2630
                               r ss ¼ N ss =N rc ¼ 1=9 ¼ 0:1111

                In the window section, the number of tubes in one window section is
             given by
                            N tw ¼ F w N t ¼ 0:1782 104 ¼ 18:53
                We also obtain the number of effective tube rows in the windows
             section as

                                     ð
                               0:8 l c   d s  d ctl Þ=2Š
                                 ½
                      N rw ¼ int
                                      s l

                                   ½
                               0:8  0:0867  0:336 0:3058Þ=2Š
                                           ð
                         ¼ int                              ¼ 3
                                          0:01768
                The shell-side flow area in the window section is calculated with
             Eq. (5.25):
                   1  2               π  2
              A sw ¼ d θ ds   sinθ ds Þ N tw d o
                      ð
                     s
                   8                  4
                   1      2                           π      2           2
                 ¼  0:336   2:131  sin 2:131ފ 18:53   0:019 ¼ 0:01287m
                             ½
                                       ð
                   8                                  4
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