Page 225 - Design and Operation of Heat Exchangers and their Networks
P. 225

214   Design and operation of heat exchangers and their networks



                                   Q _      3:563 10 5
                       t s,out ¼ t s,in    ¼ 66       ¼ 61:3°C
                                  _ m s c p,s  36:3 2077

                                    66 + 61:3  459:5  66 + 61:3  32 + 36:9
                       k s
             t s,w ¼ t s,m    ð t s,m  t t,m Þ ¼
                       α s             2     581:6       2        2
                ¼ 40:6°C

              (6)  Calculation of tube-side pressure drop
             The tube-side total pressure drop is given by

                   G 2 t     1    2        1  1     1  L  1     2
              Δp t ¼      1 σ + K c +2          +   f D     1 σ  K e
                    2 ρ                ρ    ρ    ρ       ρ
                       in               out  in   m  d i  out
                                                                    (5.90)
                The ratio of free flow area to frontal area can be expressed as
                                   2
                             σ ¼ N t d =d 2
                                   i  s                            (5.91)
                                                2
                                         2
                             ¼ 104 0:0166 =0:336 ¼ 0:2538
                The entrance and exit pressure loss coefficients for turbulent flow for a
             multiple circular-tube heat exchanger core with abrupt-contraction
             entrance and abrupt-expansion exit are correlated as follows by taking
             the data from Fig. 5-2 of Kays and London (1984). Since the inlet and
             outlet properties for seawater will not change appreciably, we use the
             mean seawater temperature to calculate its viscosity and density, that is,
             μ in ¼μ out ¼μ m , ρ in ¼ρ out ¼ρ m .
                                    "                     #

                    0:02744                0:1418   9:1465
              K c ¼ σ      0:4016 +0:4079        +
                     ln Re t                ln Re t  ð  ln Re t Þ 2

                           0:02744                  0:1418      9:1465
                ¼ 0:2538           0:4016 +0:4079          +          2
                          ln 32, 401Þ              ln 32, 401Þ  ½  ln 32, 401ފ
                                                    ð
                            ð
                                                               ð
                ¼ 0:3778
                                                                    (5.92)
                                                       !
                              0:109  0:6314    19:65
                       2σ 1+       +       2  +     3   σ
                              ln Re t  ð  ln Re t Þ  ð  ln Re t Þ
                 2
             1 σ  K e ¼
                              235
                                                 ð
                          1      +0:01277 ð 1 σ 0:25 Þ 1 σÞ
                              Re t
                                                                    !
                               0:109      0:6314       19:65
               2 0:2538  1+          +            +            0:2538
                              ð
                             ln 32, 401Þ  ½  ln 32, 401ފ 2  ½  ln 32, 401ފ 3
                                                      ð
                                         ð
             ¼
                            235
                                                    ð
                       1         +0:01277 ð 1 0:2538 0:25  Þ 1 0:2538Þ
                           32,401
             ¼ 0:3977
                                                                    (5.93)
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