Page 440 - Design and Operation of Heat Exchangers and their Networks
P. 440

Experimental methods for thermal performance of heat exchangers  423


                 Substituting Eqs. (8.132), (8.137), (8.138) into Eq. (8.131) and solving
              Eqs. (8.131), (8.133), we obtain the solution in the Laplace domain as
                                                   sNTU
                                             0          x  sBx
                                            e
                               e   Þ ¼ ϕ x, sÞθ sðÞe s + NTU e          (8.141)
                               θ x, sð  ð
              The complex coefficient φ represents the effect of the fin dynamics on the
              dynamic response of the fluid:
                      (                              2                      )
                                       2
                                      s 1 η Þ ξ ζÞ NTU     2
                                               ð
                                        ð
                                             f
              ϕ ¼ exp                                                     x
                                                              ð
                                 ð
                       ð s + NTUÞ sζ + ξNTUÞ s + NTU  1 η Þ sζ + ξNTUފ
                                                       ð
                                             ½
                                                             f
                                                                        (8.142)
              If ξ¼ζ, the fin dynamics is the same as the wall dynamics; therefore, there is
              no heat conduction along the fin height. In this case, the fins and the wall can
              be treated as one porous medium, and the traditional model can be used.
              Fig. 8.11 shows the outlet fluid temperature responses to a unit step change
              in the inlet fluid temperature, in which Bi¼4hαA f /(A c,f λ f ).
                1.0                              0.03
                    NTU= 0.1                             = 0.9
                0.9                                                 Bi = 5,    = 0.5
                                                 0.02
                0.8    0.3
                                                        0.8
                0.7    0.5                       0.01
                0.6     0.7                           0.7
               "  0.5   1                      "  max  0.00  0.6
                                                      0.5
                                                     0.4
                0.4
                         2                           0.3
                0.3                              0.01
                         3                Bi         0.2
                0.2
                          5               50     0.02
                0.1        10             10
                              20          0
                0.0                              0.03  0.1
                  0.0  0.1  0.2  0.3  0.4  0.5  0.6  0.7  0.8  0.9  1.0  0  1  2  3  4  5  6  7  8  9  10
              (A)                              (C)             NTU
                0.03                            0.018
                        = 1                          Bi = 10
                                    Bi = 5,    = 0.5  0.016           = 0.8,    = 0.5
                0.02
                       0.9
                                                0.014
                      0.8
                0.01                            0.012
                     0.7                              5
               "  max  0.00  0.6               "  max  0.010
                     0.5
                     0.4                        0.008
                      0.3
                0.01                            0.006  2
                                                0.004  1
                0.02
                       0.2                      0.002  0.5
                                                     0.2
                0.03                            0.000
                  0  1  2  3  4  5  6  7  8  9  10  0  1  2  3  4  5  6  7  8  9  10
                              NTU                              NTU
               (B)                             (D)
              Fig. 8.11 The effect of the lateral heat conduction resistance along the fin height on the
              outlet fluid temperature response to a unit step change in the inlet fluid temperature.
              (A) B¼0, ξ¼0.5, ζ ¼0.2. (B) Bi¼5, ζ¼0.5. (C) Bi¼5, ξ¼0.5. (D) ξ¼0.8, ζ¼0.5.
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