Page 170 - Design of Reinforced Masonry Structures
P. 170

4.34                       CHAPTER FOUR

               ε mu  = 0.0025         From the strain distribution diagram shown in
                                     Fig. 4.6B., we obtain Eq. (4.66) for clay masonry:
                                                    .
                                              c    0 0035
                          c                    b  =                  (4.66)
                                              d  0 0035 + ε
                                                  .
                                                         y
                                 d
                                      Substitution for yield strain in steel in terms of the
                                     yield stress [from Eq. (4.16)] in Eq. (4.66) yields
                                                     .
                                            c b  =  0 0035
                                            d        +   f y         (4.67)
                                                 .
                                                0 0035
             ε y = 0.002                              29  × 10 6
           FIGURE 4.6B Strain  distribution   where f  =  yield strength of steel reinforcement,
                                          y
           diagram for balanced conditions in a   lb/in. 2
           reinforced clay masonry beam.  E   = modulus of elasticity of steel  = 29  ×
                                          s
                                               6
                                             10  lb/in. 2
           Simplification of Eq. (4.67) yields
                                    ⎛  101 500  ⎞
                                         ,
                                 c =  ⎜        ⎟  d                  (4.68)
                                  b         +  f ⎠
                                    ⎝ 101 500,  y
             With substitutions for c  and a, as in the preceding derivation for concrete masonry,
                              b
           we obtain
                                  ⎛         ⎞ ⎛ 064.  f ′ ⎞
                                       ,
                              ρ =  ⎜  101 500  ⎟ ⎜  m ⎟              (4.69)
                               b
                                  ⎝ 101 500,  +  f y ⎠ ⎝  f  y  ⎠
             Equation (4.69) gives the balanced steel ratio, r , for clay masonry. Values of r  and
                                                                      b
                                               b
           0.75r  for clay masonry for various combinations of  ′ f  and f  are listed in Table 4.6.
               b
                                                       y
                                                  m
           In general, a beam having a reinforcement ratio r = r , the beam is called a balanced
                                                  b
         beam. When r < r , a beam is defined as an underreinforced, whereas when r > r , a beam
                      b
                                                                   b
         is defined as an overreinforced beam.
           It is important to recognize that because of the excessive amount of tensile reinforce-
         ment present (r > r ), an overreinforced beam would fail in a brittle manner, characterized
                       b
         by sudden compression failure of masonry and without yielding of tensile reinforcement.
         An underreinforced beam, on the other hand, will fail in a ductile manner, characterized
         by yielding of tensile reinforcement prior to crushing of masonry in the compression zone.
         Appendix Tables A.11 and A.12 lists values of 0.375r , 0.50r , and r max  for several practi-
                                               b
                                                     b

         cal combinations of values of  ′ f  and f  for concrete and clay masonry, respectively, which
                                    y
                               m
         are useful for design purposes.
         4.7.3  Minimum and Maximum Tensile Reinforcement in Beams
         4.7.3.1  Minimum Reinforcement Requirements  The  Code provisions for limiting
         minimum reinforcement in beams are intended to ensure a minimum amount of ductility in
         beams and to prevent brittle failures. The Code requires that the nominal strength, M , of a
                                                                     n
         beam be not less than 1.3 times the cracking moment of a beam calculated on the basis of
         moment of inertia of gross section (MSJC-08 Section 3.3.4.2.2.2). In some cases, a beam
         may be only lightly reinforced so that the reinforcement would yield under a nominal
         moment value less than the cracking moment of the beam. See Examples 4.9 and 4.10.
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