Page 172 - Design of Reinforced Masonry Structures
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4.36                       CHAPTER FOUR

         For f  = 200 psi and f  = 60,000 psi, the above expression yields
                        y
            r
                        ρ  =  A s  =  . 0 3284  ⎛ 200  ⎞ ⎟  =  . 0 001097  ≈  . 0 00011
                                     ⎜
                        min                ⎠
                            bd       ⎝ 60 ,000
                     9"               The above result means that a reinforced beam,
                                   with  r  = 0.0011 would have its nominal strength
                                   equal to 1.3 times the nominal cracking moment.
                                   Accordingly,  r  = 0.0011 may be considered as
                                   the minimum reinforcement ratio for a reinforced
                                   masonry beam. See Example 4.12.


                                   Example 4.12  A 9- × 24-in. brick beam is rein-
                               20"
           24"                     forced with a No. 4 Grade 60 bars placed at 20 in.
                                   from the compression face of the beam (Fig. E4.12).
                                   Calculate for this beam (a) the nominal cracking
                                   moment, (b) nominal moment strength, and (c) check
                                   if the beam complies with the code requirements.  ′ f  =
                                                                       m
                                   1500 psi.
                                   Solution
                     #4
                                      Given: b = 9 in., h = 24 in., d = 20 in. f  = 200 psi
                                                                  r
                                                                2
           FIGURE E4.12  Beam cross sec-  (MSJC-08 Table 3.1.8.2.1). A  = 0.20 in. .
                                                         s
           tion for Example 4.12.  a.  Calculate nominal cracking moment of the beam
                                     from Eq. (4.54):
                          ⎛ bh ⎞     ⎛ 924()(  ) 2 ⎞ ⎛  1  ⎞
                             2
                    M =  f r ⎜  ⎟  = 200(  ) ⎜  ⎟ ⎜  ⎟  = 14 4 . k-ft
                      cr      ⎠      ⎝       ⎝    0 0⎠
                          ⎝ 6            6  ⎠ 12 00,
             b.  Calculate the nominal moment strength of the beam. From Eq. (4.9)
                                Af     (.  ) (
                                        020 60)
                            a =  sy  =         = 111 iin.
                                                  .
                                       .
                                            )
                                          (
                                           .
                                             (
                              080  fb ′  080 15 9)
                               .
                                  m
                From Eq. (4.12), the nominal strength of the beam is
                                         ⎛
                                               .
                   M =  A f  ⎛ ⎝ d −  a ⎞ ⎠ 2  = 020 60 20 −  111 ⎞ ⎛ 1  ⎞ ⎠  = 19 45 k-ft
                                      (
                                                         .
                                         )
                                  (.
                                         ⎝
                                                 ⎠ ⎝ 12 ⎠
                     n
                         s y
                                               2

             c. M  = 19.45 k-ft > 1.3M  = 1.3(14.4) = 18.72 k-ft. Therefore, the beam complies
                                cr
                 n
                with the code requirement. Note that r = A /bd = 0.20/(9)(20) = 0.0011.
                                              s
         4.7.3.2 Maximum Reinforcement Requirements  The code provisions for maximum
         reinforcement in beams are intended to ensure that the reinforcement would yield suffi-
         ciently so that the beam would exhibit a ductile behavior.
           MSJC-08 Section 3.3.3.5.1 requires that for masonry members where the quantity
         M / V d  ≥ 1, the cross-sectional area of reinforcement shall not exceed the area required to
          u   u v
         maintaining a strain gradient corresponding to a strain in the reinforcing bar nearest the ten-
         sion face of the member equal to 1.5 times the yield strain (i.e., 1.5e ) and a maximum strain
                                                        y
         in masonry specified in MSJC Section 3.3.2(c) (i.e., e  = 0.0025 for concrete masonry
                                                mu
         and 0.0035 for clay masonry). This code provision is intended to ensure that masonry
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