Page 168 - Determinants and Their Applications in Mathematical Physics
P. 168

4.12 Hankelians 5  153
          4.12    Hankelians 5


          Notes in orthogonal and other polynomials are given in Appendices A.5 and
          A.6. Hankelians whose elements are polynomials have been evaluated by a
          variety of methods by Geronimus, Beckenbach et al., Lawden, Burchnall,
          Seidel, Karlin and Szeg¨o, Das, and others. Burchnall’s methods apply the
          Appell equation but otherwise have little in common with the proof of the
          first theorem in which L m (x) is the simple Laguerre polynomial.


          4.12.1  Orthogonal Polynomials
          Theorem 4.54.
                           (−1) n(n−1)/2 0! 1! 2! ··· (n − 2)!  n(n−1)
                |L m (x)| n =                         x     ,  n ≥ 2.
                           n!(n + 1)! (n + 2)! ··· (2n − 2)!
               0≤m≤2n−2
          Proof. Let

                                                1
                                                   ,
                                         m
                                                x
                                φ m (x)= x L m
          then

                                 φ (x)= mφ m−1 (x),
                                  m
                                    φ 0 =1.                         (4.12.1)
          Hence, φ m is an Appell polynomial in which
                                           (−1) m
                                  φ m (0) =      .
                                            m!
          Applying Theorem 4.33 in Section 4.9.1 on Hankelians with Appell polyno-
          mial elements and Theorem 4.47b in Section 4.11.3 on determinants with
          binomial and factorial elements,


                             1
                      m           = |φ m (x)| n ,  0 ≤ m ≤ 2n − 2
                       x L m  x
                                n
                                  = |φ m (0)| n

                                         m
                                      (−1)
                                  =
                                       m!
                                           n

                                      1
                                  =
                                     m!

                                        n
                                    (−1) n(n−1)/2 0! 1! 2! ··· (n − 2)!
                                  =                            .    (4.12.2)
                                    n!(n + 1)! (n + 2)! ··· (2n − 2)!
          But


                                  1                  1
                           m           = x  n(n−1)         .        (4.12.3)
                            x L m  x               L m  x
                                     n                   n
   163   164   165   166   167   168   169   170   171   172   173