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Image Enhancement       235

               where

                                        V
                              r =  r =   ij                         (6.16)
                                       V × V
                               ij  ji
                                        ii  jj
                                     V        214
                                               .
                             r =      12   =       = .
                                                    044
                              12
                                   V ×  V     6 ×  4
                                    11   22
                                  ⎛ 100 044⎞
                                    .
                                         .
                              R = ⎜        ⎟
                                  ⎝ 044 100⎠
                                         .
                                    .
                   In other words, 44 percent of information is shared between bands
               1 and 2 as illustrated in Fig. 6.22. The variance matrix after transforma-
               tion must meet the following condition:
                                     |V − k I| = 0                  (6.17)
               where I = identity matrix; k = eigen value matrix. It has the fol-
               lowing form:
                                   ⎛λ   0  ...  0 ⎞
                                   ⎜  1  λ       ⎟
                                k  = ⎜  0  2  ...  0  ⎟
                                   ⎜ ...  ... ...  0  ⎟
                                   ⎜ ⎝ 0  0  ...  λ n ⎟ ⎟ ⎠


                   Plugging the V and I matrices into Eq. (6.17) yields the following
               formula:

                  ⎛  6   2 14⎞   ⎛ 10⎞               6 − λλ  214 0
                                                                 −
                          .
                                                             ..
                  ⎜ ⎝ 214  4 ⎠ ⎟  − l  ⎜ ⎝ 01⎠ ⎟  = 0  or    214 0  4 − λλ  = 0
                                                        −
                    .
                                                     .
                   Or (6 − l)(4 − l) − 2.14 × 2.14 = 0
                   So l = 7.36    l = 2.76
                      1          2
                   The eigen value matrix k after the transformation is
                                             .
                                        .
                                   k =  ⎛ ⎜ ⎝ 736 000⎞ ⎟
                                       000 264⎠
                                        .
                                             .
                   The following three points should be noted from the variance-
               covariance matrix V and the eigen value matrix k:
                    •  The total variance of the two spectral bands (6 + 4 = 10) before
                      the transformation is exactly the same as the total eigen values
                      (the main diagonal elements) (7.36  + 2.64  = 10) after the
                      transformation. This clearly demonstrates that PCA does not
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