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0593_C12_fm  Page 427  Monday, May 6, 2002  3:11 PM





                       Generalized Dynamics: Kane’s Equations and Lagrange’s Equations             427


                        In Section 11.12, we found the kinetic energy of the system to be (see Eq. (11.12.13)):

                                            K = ( ) ml θ 2  +(1  m ) 2  l θ θ  cos θ  − )
                                                      2 ˙
                                                                              θ
                                                                  2 ˙ ˙
                                                23
                                                        1           1  2  ( 2  1
                                                                                              (12.3.19)
                                                        2 ˙
                                                +(16  m ) l θ  2
                                                          2
                        As with the single-rod pendulum, gravitational forces are the only forces doing work
                       on the system. In Section 11.11, we found the potential energy P of the gravitational forces
                       to be (see Eq. (11.11.5)):
                                                        P =  mgh +  mgh                       (12.3.20)
                                                              1     2
                       where h  and h  are the elevations of the rod mass centers G  and G  above an arbitrary
                                                                                    2
                              1
                                                                             1
                                    2
                       but fixed reference level. If, as before, we take the reference level through the support O
                       we find h  and h  to be (see Figure 12.3.3):
                                     2
                               1
                                         h =−(l  2)cosθ     and     h =−lcosθ  −(l  2)cosθ    (12.3.21)
                                          1           1        2        1          2
                       where, as before, each rod has length   and mass m.
                        Using Eqs. (12.3.19) and (12.3.20), the Lagrangian L becomes:

                                              −
                                                                                 θ
                                                                     2 ˙ ˙
                                                         2 ˙
                                         L =  K P = ( ) ml θ 2  +(1  m ) 2  l θ θ  cos θ  − )
                                                   23
                                                            1          1  2  ( 2  1
                                                     2 ˙
                                                             l
                                             +(16  m ) l θ 2  = ( mg ) 2 cosθ                 (12.3.22)
                                                       2             1
                                             + mglcosθ  +( mg ) 2 cosθ
                                                            l
                                                      1            2
                       Substituting L into Lagrange’s equations, Eq. (12.3.5) then produces the expressions:
                                  ( 4 3)θ 1 +( 12)θ 2  cos  2 (θ  − θ 1) −( 12)θ 2 ˙  2  sin  2 (θ  − θ 1) +  3 ( g  2 )sinθ 1  =  0  (12.3.23)
                                              ˙˙
                                      ˙˙
                                                                                 l
                                  ( 12)cos θ 2 (  − θ 1)θ ˙˙ 1  +( 13)θ 2 −( 12)θ 2 1  sin  1 (θ  − θ 2) +(g  2 ) sinθ 2  =  0  (12.3.24)
                                                        ˙˙
                                                                                 l
                        Eqs. (12.3.23) and (12.3.24) are identical to Eqs. (8.10.12) and (8.10.13) obtained using
                       d’Alembert’s principle, and Eqs. (12.2.22) and (12.2.23) using Kane’s equations. Comparing
                       the three approaches it should be clear that Lagrange’s equations produce the governing
                       equations with the least amount of analysis effort.

                       Example 12.3.4: Spring-Supported Particles in a Rotating Tube
                       Finally, consider the system of spring-supported particles in a rotating tube as in Figure
                       12.3.4. We considered this system in Sections 11.7, 11.10, 11.11, 11.12, and 12.12. Recall that
                       the system has four degrees of freedom represented by the angle θ and the coordinates
                       x , x , and x  as in Figure 12.3.5.
                                 3
                        1
                          2
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