Page 460 - Dynamics of Mechanical Systems
P. 460

0593_C13_fm  Page 441  Monday, May 6, 2002  3:21 PM





                       Introduction to Vibrations                                                  441


                       As noted earlier, the constants in Eqs. (13.2.2) and (13.2.3) are to be evaluated by auxiliary
                       conditions. These auxiliary conditions are generally initial conditions or boundary condi-
                       tions. Initial conditions (where t = 0) might be expressed as:

                                                   x 0 () =  x     and     ˙ x 0 () = ˙ x      (13.2.9)
                                                          0              0

                       Then, by requiring the solution of Eq. (13.2.2) to meet these conditions, we have:

                                                    A =  x     and     B x ˙ ω                (13.2.10)
                                                                   =
                                                         0           0
                       and thus,

                                                   x = x cosω   x ˙ ω )sinω t                  (13.2.11)
                                                       0    t +( 0

                        Boundary conditions might be expressed as:

                                                    x 0 () =  0    and     x() =  0           (13.2.12)
                                                                    l

                       Then, by requiring the solution of Eq. (13.2.2) to meet these conditions, we see that the
                       constants A and B must satisfy:


                                                    A = 0    and     Bsinωl  = 0              (13.2.13)

                       The second expression is satisfied by either:

                                                     B = 0    or    sinωl  = 0                (13.2.14)

                        If B = 0, we have the trivial solution x = 0. Alternatively, if sinω  = 0, ω  must be an
                       integer multiple of π. That is,

                                                  ωl = n π    or     ω =  ω = n π l           (13.2.15)
                                                                    n
                       Thus, there is a nontrivial solution only for selected values of ω — that is, for ω = nπ/ .
                       The solution for the displacement then takes the multiple forms:

                                                              π
                                                x =  x =  B sin  n t l  n = , , …             (13.2.16)
                                                                       12
                                                     n   n
                       Then, by superposition, we have:

                                                           ∞
                                                      x = ∑  B sin n t l                      (13.2.17)
                                                                   π
                                                              n
                                                          n=1
                       where the constants B  are to be determined from other conditions of the specific system
                                          n
                       being studied. (Eq. (13.2.17) is a Fourier series representation of the solution.)
   455   456   457   458   459   460   461   462   463   464   465