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108                           The band theory of solids

                                     The integration in eqn (7.19) can be easily performed, but we are not really
      E
                                   interested in the actual numerical values. The important thing is that V n  = 0
                                   and has opposite signs for the wave functions ψ ± .
                                     Let us go through the argument again. If the electron waves have certain
                                   wave numbers [satisfying eqn (7.15)], they are reflected by the lattice. For each
                                   value of k two distinct wave functions ψ + and ψ – can be constructed, and the
                                   corresponding potential energies turn out to be +V n and –V n .
                                     The kinetic energies are the same for both wave functions, namely

                                                                  2 2
                                                                   k
                                                              E =    .                      (7.21)
                                                                  2m
                E+
                                   Thus, the total energies are
                E–
                                                                 2 2
                                                                  k
                               k                           E ± =    ± V n .                 (7.22)
              π/a                                               2m
                                   This is shown in Fig. 7.7 for k = π/a. The energy of the electron may be
     Fig. 7.7
     The two possible values of the                      k            k
                                                        2 2
                                                                      2 2
     electron’s total energy at k = π/a.                   – V 1  or     + V 1 ,            (7.23)
                                                       2m            2m
                                   but cannot be any value in between. There is an energy gap.
                                     What will happen when k  = nπ/a? The same argument can be developed
     ∗  J.M. Ziman, Electrons in metals, a  further, and a general form may be obtained for the energy. ∗
     short guide to the Fermi surface,Taylor  It is, however, not unreasonable to assume that apart from the discontinuities
     and Francis, 1962.
                                   already mentioned, the E–k curve will proceed smoothly; so we could construct
                                   it in the following manner. Draw the free electron parabola (dotted lines in
                                   Fig. 7.8) add and subtract V n at the points k = nπ/a, and connect the end
                                   points with a smooth curve, keeping close to the parabola. Not unexpectedly,
                                   Fig. 7.8 looks like Fig. 7.5, obtained from the Kronig–Penney model.


                                               E

                                                                                  2V
                                                                                    3








                                                                                  2V
                                                                                    2



                                                                                  2V 1

     Fig. 7.8                                            π       2π       3π      k
     Construction of the E–k curve from                  a        a       a
     the free-electron parabola.
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