Page 408 - Electromagnetics
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The magnetic field components are found using (5.161) and (5.163):
                                                                    ˜
                                                           1   1  ∂ A e
                                                      ˜
                                                      H θ =           ,                       (5.169)
                                                           ˜ µ r sin θ ∂φ
                                                                 ˜
                                                      ˜      1 1 ∂ A e
                                                      H φ =−       .                          (5.170)
                                                             ˜ µ r ∂θ
                         2. TE fields.   To generate fields TE to r we recall that the electromagnetic fields in
                        a source-free region may be written in terms of magnetic vector and scalar potentials as
                                                      ˜
                                                              ˜
                                                     H =− jωA h −∇φ h ,                       (5.171)
                                                                ˜
                                                      ˜
                                                     D =−∇ × A h .                            (5.172)
                        In a source-free region we have from Faraday’s law
                                                  1              1
                                           ˜               ˜                  ˜
                                           H =         ∇× D =        ∇× (∇× A h ).
                                               − jω ˜µ˜  c     jω ˜µ˜  c
                                   ˜
                             ˜
                        Here φ h and A h must satisfy a differential equation that may be derived by examining
                                                             ˜
                                                                           ˜
                                                                    c
                                                                                 2 ˜
                                                  ˜
                                        ∇× (∇× H) = jω∇× D = jω˜  (− jω ˜µH) = k H,
                                   2
                                       c
                               2
                        where k = ω ˜µ˜  . Substitution from (5.171) gives
                                                       ˜
                                                                                ˜
                                                                          ˜
                                                             ˜
                                                                	   2
                                         ∇× ∇× [− jωA h −∇φ h ] = k [− jωA h −∇φ h ]
                        or
                                                                      k 2
                                                         ˜     2 ˜        ˜
                                                ∇× (∇× A h ) − k A h =  ∇φ h .                (5.173)
                                                                      jω
                                       ˜
                                 ˜
                        Choosing A h = ˆ rA h and
                                                                  ˜
                                                         ˜    jω ∂ A h
                                                        φ h =
                                                              k 2  ∂r
                        we find, as with the TM fields,
                                                               ˜ A h

                                                       2
                                                            2
                                                     (∇ + k )      = 0.                       (5.174)
                                                                r
                                         ˜
                        Thus the quantity A h /r obeys the Helmholtz equation.
                          We can find the TE fields using (5.171) and (5.172). Substituting we find that
                                                         1   
  ∂ 2
                                                  ˜                  2  ˜
                                                  H r =           + k   A h ,                 (5.175)
                                                       jω ˜µ˜  c  ∂r  2
                                                               2 ˜
                                                         1   1 ∂ A h
                                                  ˜
                                                  H θ =            ,                          (5.176)
                                                            c
                                                       jω ˜µ˜  r ∂r∂θ
                                                                   2 ˜
                                                         1     1  ∂ A h
                                                  ˜
                                                 H φ =                 ,                      (5.177)
                                                            c
                                                       jω ˜µ˜  r sin θ ∂r∂φ
                                                                  ˜
                                                         1   1  ∂ A h
                                                  ˜
                                                  E θ =−            ,                         (5.178)
                                                         c
                                                         ˜   r sin θ ∂φ
                                                            ˜
                                                  ˜    1 1 ∂ A h
                                                  E φ =       .                               (5.179)
                                                        c
                                                       ˜   r ∂θ
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