Page 173 - Elements of Chemical Reaction Engineering 3rd Edition
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Sec. 4..2   Scale-up of  Liquid-Phase Batch Reactor Data to the Design of  a CSTR   145

                                        where
                                                               1 ft3
                                           z== -=~galx~al)x                      = 13.94 inin
                                                V
                                               v0/2                    7.67 ft3/min
                                        The Damkiihler number is

                                                    Da = 7k = 13.94 min X 0.311 = 4.34
                                                                        min
                                        Substituting into Equation (E%-2.5) gives us

                                                          x= -_ 4'34  - 0.81
                                                              1 i- 4.34
                                      7. CSTRs in series. If the 800-gal reactors are arrmged in series, the cwmion
                                        in the first reactor is
                                                                    9 k
                                                              x, = -                        W-2.6)
                                                                   1+T,k
                                        where





                                        The Dmkohler number is
                                                    Da,  =: ~,k 6.97 min X os
                                                            =
                                                                        rnin   =  2.167
                                                          x,= 2'167 - 0.684
                                                               --
                                                               3.167
                                        To  calculate  the  conversion  exiting  the  second  reactor,  we  recall  that
                                        V1 = V2 = V and  uol = vO2 = vo ; then

                                                                 = 7.2 = 7
                                        Combining the  mole  balance on  the  second reactor  with the  rate  law, we
                                        obtain





                                        Solving for the conversion exiting the second reactor yields




                                        The same result could have been obtained from Equation (4-1 1):
                                                  x=1---  1     -1-            = 0.90
                                                         (1 47k)n    (1 +2.167)2
                                        Two hundred  million pounds  of  ethylene glycol  per  year can  be  produced
                                        using two 800-gal (3.0-m3) reactors in series.
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