Page 259 - Elements of Chemical Reaction Engineering 3rd Edition
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Sec. 5.1   Batch Reactor Data                                  23 1

                     Mole balance   Taking the natural logarithm of  both sides gives us
                    in terms of the
                        measured
                       variable, P                                                           (E,5-1.6)

                                                       I                       I
                                   Observe that the reaction order,  (Y,  can be determined from  the slope of  a plot of
                                   InldPIdt) versus ln(3Po- P). Once (Y  is known, the constant k'  may be calculated
                                   from the ratio

                                                                                             (E5- 1.7)


                                   at any point.
                                     3.  Look for simpl%kations.  We  have  assumed  the  reaction  is  irreversible.
                                   Check to see if  any  terms in the equation can be neglected [e.g., the term  EX  in
                                   (1 -1 EX) when (EX< 111.
                                      4.  Determine dPIcit from the pressure-time data and then the reaction order a.
                                   The data are reported in terms of total pressure as a function of time; consequenrly,
                             dP
                      First find  ;i;   we must differentiate the data either numerically or graphically before we can use
                                    Equations (E5-1.6) and (E5- 1.7) to evaluate the reaction order and specific reaction
                                    rate.  First  we  shall  evaluate  dPldt  by  graphical differentiation. Many  prefer  the
                                    graphical analysis because they use it to visualize the discrepancies in their data.

                 Graphical method is   GraphicaE Method. The derivative dPldt is determined by  calculating and plotting
                   used to visualize   AP/At  as a function of time, r, and then using the equal-area differentiation tech-
                 discrepancies in data   nique (Appendix A.2) to determine (dPldr) as a function of P and r, First we calcu-
                                    late the ratio NPIAi from the first two columns of Table E5-1.2; the result is written
                                    in the third column. Next we use Table E5-1.2 to plot the third column as a function
                                    of  the first column in Figure E5- 1.1. Using equal-area differentiation, the value of
                                    dP/,dt is read off the figure (represented by  the arrows) and then it is used to com-
                                    plete the fourth column of Table E5-1.2.


                                                        TABLE E5-1.2.  PROCESSED DATA
                                                                     AP           dP
                                                                     -
                                                                                  -
                                                                                  dt
                                                                     At
                                                           P
                                                 20.0  3
                                                t (min)   (mmHg)   (mmHg/min)   (mmHg/min)
                                                  0.0
                                                                                 1.44
                                                                     1.20
                                                  2.5
                                                                                 0.95
                                                                     0.80
                                                  5.0
                                                                                 0.74
                                                                     0.66
                                                 10.0
                                                                                 0.53
                                                          15.8
                                                                     0.42
                                                 15.0
                                                          17.9
                                                                     0.30
                                                          19.4
                                                                                 0.25
                                                            Temperature  = 170°C   0.34
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