Page 288 - Finite Element Modeling and Simulations with ANSYS Workbench
P. 288

Structural Vibration and Dynamics                                           273



                              u(t)
                                   u 1


                                                     u k  u k + 1
                                      u 2




                                 t 0  t 1  t 2        t k  t k + 1     t

            FIGURE 8.9
            Computing the responses by integration through time.



              To compute the transient responses, integration through time is employed (Figure 8.9).
              We write the equation of motion at instance t , k = 0, 1, 2, 3, …, as
                                                     k

                                         Mu    +  Cu   +  Ku k =                       (8.31)
                                             k    k         f k

              Then, we introduce time increments: Δt = t k + 1  − t , k = 0, 1, 2, 3, …, and integrate through
                                                        k
            the time.
              There are two categories of methods for transient analysis as described in the following
            sections.


            8.5.1  Direct Methods (Direct Integration Methods)
            Central Difference Method:
            Approximate the velocity and acceleration vectors by using finite difference:

                                             1
                                         u k =  ( u k+1  −  u k−1 ),
                                            2∆ t                                      (8.32)
                                             1
                                          u k =  2  ( u k+1  − 2 u k +  u k−1 )
                                              t ∆ ()


              Dynamic equation becomes,


                             1                       1           
                                               1 ) +
                        M     2  u (  k+ 1 −  2 u k +  u k−   C   u (  k+ 1 −  u k− 1 ) +  Ku k =  f k
                                                                    
                            ∆
                              t
                            ()                      2∆t          
            which yields

                                              Au k+ =  F t()                          (8.33)
                                                  1
   283   284   285   286   287   288   289   290   291   292   293