Page 47 - Fundamentals of Radar Signal Processing
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= sinθ can only range from –1 to +1. Because of this,                is zero outside of this
               range on s.
                     Equation (1.5) is a somewhat simplified expression that neglects a range-
               dependent  overall  phase  factor  and  a  slight  amplitude  dependence  on  range
               (Balanis,  2005).  This  Fourier  transform  property  of  antenna  patterns  will,  in

               Chap. 2, allow the use of linear system concepts to understand the effects of the
               antenna on cross-range resolution and the pulse repetition frequencies needed to
               avoid spatial aliasing.
                     An  important  special  case  of Eq. (1.5) occurs when the aperture current
               illumination is a constant, A(y) = A . The normalized far-field voltage pattern is
                                                         0
               then the familiar sinc function,







                                                                                                        (1.8)

               If the aperture current illumination is separable, then the far-field is the product
               of two Fourier transforms, one in azimuth (θ) and one in elevation (ϕ).
                     The magnitude of E(θ) is illustrated in Fig. 1.6, along with the definitions
               for two important figures of merit of an antenna pattern. The angular resolution

               of the antenna is determined by the width of its mainlobe, and is conventionally
               expressed  in  terms  of  the 3-dB  beamwidth.  This  can  be  found  by  setting
                             and  solving  for  the  argument α  = π(D /λ) sinθ. The answer can be
                                                                           y
               found numerically to be α = 1.4, which gives the value of θ at the –3-dB point
               as θ  = 0.445λ/D . The 3-dB beamwidth extends from –θ  to +θ  and is therefore
                                                                                          0
                                                                                  0
                    0
                                   y
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