Page 390 - Fundamentals of Reservoir Engineering
P. 390

NATURAL WATER INFLUX                                   325

                     For the first time step p a n-1  = p i, the initial reservoir and aquifer pressure.


                     The constant terms in equs. (9.28) and (9.29) can be evaluated (in field units), for the
                     correct aquifer size, i.e. r eD = 5, as follows:

                           W ei  =  cWp
                                     i i
                               =  cfπ ( e 2  r  2 o ) h p / 5.615 rb
                                              φ
                                       r −
                                                i
                                        6
                                                                   6
                                        −
                                                 ×
                                    ×
                                  7 10 ×   .3889 π  (2116 85) 10 ×    100 .25 2740
                                                          −
                                                                          ×
                                                                               ×
                                                               ×
                               =
                                                         5.615
                           W ei  =  211.9 MMrb
                     For a finite radial aquifer
                                           3
                                           −
                                  7.08 10 fkh
                                       ×
                           J   =
                                        r   3
                                   µ   ln  e  −
                                        r o  4                                                      (9.30)
                                           3
                                           −
                                  7.08 10 ×   .3889 200 100
                                                    ×
                                       ×
                                                          ×
                               =                               = 116.5b / d/psi
                                          .55(In5 .75)
                                                 −
                     Therefore, Jp i/W ei   = 116.5×2740/211.9×10  6
                                                       -3
                                            = 1.506×10  /day
                     Since the ∆t in equ. (9.28) is in days, then for time steps of one year
                                                            3
                                                           −
                                   ∆
                               − Jp t / W       − 1.506 10 ×   365 =  0.4229
                                                       ×
                           1e     i     ei  = −
                                            1e
                            −
                     Equ. (9.28) can therefore be reduced to
                                  211.9 10  6
                                        ×
                           ∆ W =             ( p  − p  ) × 0.4229
                               n e   2740       a n 1  n
                                                 −
                           ∆ W =  32705  ( p  − p  ) rb
                               n e         a n 1  n
                                            −
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