Page 62 - Fundamentals of The Finite Element Method for Heat and Fluid Flow
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54
                        and
                                                                                            (3.62)
                                                        L k =  y   THE FINITE ELEMENT METHOD
                                                              2.5
                           From Equation 3.55, we get
                                                             x    y
                                                     L i = 1 −  −                           (3.63)
                                                             4   2.5
                           At (x, y) = (2, 1),wehave
                                                      L i = 0.1 = N i
                                                      L j = 0.5 = N j

                                                      L k = 0.4 = N k                       (3.64)
                           Note that these local coordinates are exactly the same as the shape function values
                        calculated in Example 3.2.2


                        3.2.5 Quadratic triangular elements

                        We can write a quadratic approximation over a triangular element as
                                                                       2
                                                                 2
                                          T = α 1 + α 2 x + α 3 y + α 4 x + α 5 y + α 6 xy  (3.65)
                           Since there are six arbitrary constants, the quadratic triangle will have six nodes
                        (Figure 3.10). The six constants α 1 ,α 2 ,... ,α 6 can be evaluated by substitution of the
                        nodal coordinates and the corresponding nodal temperatures T 1 ,T 2 ,... ,T 6 . For example,
                        we can write the following relationship for the first node:

                                                                 2      2
                                        T 1 = α 1 + α 2 x 1 + α 3 y 1 + α 4 x + α 5 y + α 6 x 1 y 1  (3.66)
                                                                 1     1
                           Once α 1 ,α 2 ,... ,α 6 are determined, then the substitution of these parameters into
                        Equation 3.65 and collating the coefficients of T 1 ,T 2 ,... ,T 6 , give relations for the shape
                        functions. The process is both tedious and unnecessary. A much superior and more general


                                                y
                                                        5


                                                              4
                                                    6


                                                                    3
                                                            2
                                                    1
                                                                        x
                                          Figure 3.10  A quadratic triangular element
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