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784                                                                 Appendix C: Miscellaneous Relations



                                             P abs =P atm +P gage
                                   Pressure of point A
                                                    P gage
                                                                          P abs =P atm +P gage
                                Atmospheric pressure            Atmospheric pressure
                                                                                  P gage
                                                         P abs
                                                    P atm        Pressure of point A     P atm

                                                                                  P abs
                                (a)       Datum                 (b)      Datum
            FIGURE C.1  Graphical and algebraic pressure relations for conversions between absolute pressure and gage pressure. Pressure at level A is
            the focus. (a) Positive gage pressure. (b) Negative gage pressure (vacuum).



            C.3.3 NATURAL LOGARITHMS
                                                               TABLE C.1
            In converting between common log and natural log values, the  Amount after k Periods of Compounding
            rationale must be reconstructed (unless this task is done
                                                               P         n        r           k             A
            often). This section provides a review of the basics and can
            also be used more expediently to glean only the immediate  1.00  1   1.00      1             2.00000000
            needs of a conversion.                                                         10            2.59374246
                                                                                           100           2.70481383
            C.3.3.1  Compound Interest                                                     1,000         2.71692393
            We may look at say the way money is compounded as an                           10,000        2.71814593
            introduction as to how some things happen in nature, say                       100,000       2.71826824
            growth of a bacterial culture. Consider the money problem                      1,000,000     2.71828047
            first. The rate at which a sum of money grows depends on the
            rate of interest, r. Suppose r ¼ 0.06=year (i.e., 6% per annum)
            and the principal, P ¼ $1.00. The amount, A, accumulated at  C.3.3.3  The Number e
                                                                                                      k
            the end of 1 year is $1.06, i.e., A ¼ P(1 þ r). After 2 years, i.e.,  The limit approached by the quantity, (1 þ 1=k) is denoted
                                                               by e:
            n ¼ 2, A(2 year) ¼ A(1 year)   (1 þ r) ¼ [P(1 þ r)]   (1 þ r) ¼
                  2
            P(1 þ r) . After n years
                                                                                               k
                                                                                            1
                             A(n) ¼ P(1 þ r) n           (C:6)                  e ¼ L    1 þ                (C:8)
                                                                                   k!1      k
            Now suppose the interest is compounded every half year.              ¼ 2:71828                  (C:9)
            For this case, r(0.5 year) ¼ 0.03, or r=2, and the formula is,
                        2n
            A(n) ¼ P(þr=2) . To generalize, if we let the value be com-  and
            pounded k times per year, then
                                                                                log e ¼ 0:43429426         (C:10)
                                           kn
                                     1 þ r
                            A(n) ¼ P                     (C:7)
                                       k                       Therefore, $1 with 100% interest, compounded continuously
                                                               for 1 year would result in e dollars. The limiting value of A in
            in which                                           (C.6) is
              A(n) is the compounded amount at the end of n years
              P is the principal amount at t ¼ 0                                    A ¼ Pe rn              (C:11)
              r is the annual rate
              n is the number of years                         which is the amount of any principal, P, after n years with
              k is the number of times interest is compounded each year  interest compounded continuously at any rate, r.
            C.3.3.2  Continuous Growth                         C.3.3.4  Kinetics
            Now suppose we compound the interest very often, or continu-  For any physical quantity that increases or decreases at a rate
            ously. The rate of growth is then proportional to the amount at  proportional to the concentration, the expression is
            any instant. To illustrate, let, P ¼ 1.00, n ¼ 1, r ¼ 1.00, and let
            k ¼ 1,10, 100,1000. Table C.1 shows the amounts, A, for each k.         dA  ¼ rA               (C:12)
              The limiting value of A is seen to be 2.718.                           dt
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