Page 706 - Handbook Of Integral Equations
P. 706

2
                          dx           1        1      x
               59.              =            +              .

                                       2
                         2
                             2 2
                                    2
                                           2
                                                      2
                       x(a – x )  2a (a – x )  2a 4  ln  a – x 2
                          dx           1            1        1      x
                                                                     2
               60.              =             +           +              .

                                                  4
                                           2 2
                         2
                                                        2
                                    2
                                                    2
                                       2
                             2 3
                                                                   2
                       x(a – x )  4a (a – x )   2a (a – x )  2a 6  ln   a – x 2
                                          3
                                     3
                 Integrals containing a + x .
                        dx      1      (a + x)     1        2x – a
                                            2
               61.           =     ln           +  √ arctan   √   .
                        3
                                      2
                       a + x 3  6a 2  a – ax + x 2  a 2  3   a 3
                         dx           x        2      dx

               62.             =            +             .
                            3 2
                                   3
                                                     3
                                          3
                                      3
                        3
                       (a + x )  3a (a + x )  3a 3  a + x 3
                        xdx     1   a – ax + x    1        2x – a
                                     2       2
               63.           =    ln           + √ arctan   √   .
                        3
                       a + x 3  6a    (a + x) 2  a 3       a 3
                         xdx         x         1     xdx
                                       2
               64.             =            +             .
                                                     3
                                          3
                                   3
                            3 2
                                      3
                        3
                       (a + x )  3a (a + x )  3a 3  a + x 3
                       x dx    1    3   3
                        2
               65.           =   ln |a + x |.
                        3
                       a + x 3  3
                          dx       1      x
                                           3
               66.              =              .

                         3
                                         3
                             3
                       x(a + x )  3a 3  ln   a + x 3
                          dx           1        1      x
                                                        3
               67.               =           +              .

                                                      3
                             3 2
                                       3
                         3
                                     3
                                           3
                       x(a + x )   3a (a + x )  3a 6  ln   a + x 3

                          dx         1    1    xdx
               68.               = –   –            .
                                               3
                        2
                              3
                                     3
                          3
                       x (a + x )   a x  a 3  a + x 3
                          dx         1        x        4      xdx
                                               2
               69.               = –    –            –             .
                                              3
                                                  3
                        2
                              3 2
                                            6
                                                              3
                          3
                                     6
                       x (a + x )   a x   3a (a + x )  3a 6  a + x 3
                                          3
                                     3
                 Integrals containing a – x .
                        dx      1    a + ax + x    1        2x + a
                                      2       2
               70.           =     ln           +  √ arctan   √   .
                        3
                       a – x 3  6a 2   (a – x) 2  a 2  3     a 3
                         dx           x        2      dx

               71.             =            +             .
                                      3
                                                     3
                                   3
                            3 2
                                          3
                        3
                       (a – x )  3a (a – x )  3a 3  a – x 3
                        xdx     1   a + ax + x    1        2x + a
                                     2       2
               72.           =    ln           – √ arctan   √   .
                        3
                       a – x 3  6a    (a – x) 2  a 3       a 3
                         xdx         x         1     xdx
                                      2
               73.             =            +             .
                                      3
                            3 2
                        3
                                   3
                                          3
                                                     3
                       (a – x )  3a (a – x )  3a 3  a – x 3
                       x dx     1    3   3
                        2
               74.           = –  ln |a – x |.
                        3
                       a – x 3  3
                          dx       1      x
                                           3
               75.              =              .

                                         3
                             3
                         3
                       x(a – x )  3a 3  ln   a – x 3
                          dx           1        1      x
                                                        3
               76.              =            +              .

                             3 2
                                    3
                         3
                                                      3
                                       3
                                           3
                       x(a – x )  3a (a – x )  3a 6  ln  a – x 3

                          dx        1     1    xdx
               77.              = –    +            .
                                    3
                        2
                              3
                          3
                                               3
                       x (a – x )  a x   a 3  a – x 3
                          dx         1        x        4      xdx
                                               2
               78.               = –    –           +              .
                                                              3
                          3
                              3 2
                                     6
                                            6
                                              3
                        2
                                                  3
                       x (a – x )   a x   3a (a – x )  3a 6  a – x 3
                 © 1998 by CRC Press LLC
               © 1998 by CRC Press LLC
                                                                                                             Page 690
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