Page 115 - Handbook of Civil Engineering Calculations, Second Edition
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1.98            STRUCTURAL STEEL ENGINEERING AND DESIGN














                                 FIGURE 7




                                                                                          2
                            The excess area   hole area – allowable area   4.00 – 3.13   0.87 sq.in. (5.613 cm ).
                            Consider that this excess area is removed from the outstanding legs of the angles, at both
                            the top and the bottom.
                            4. Compute the moment of inertia of the net section


                                                                   in 4        dm 4
                                                                   3,456      14.384
                                   One web plate, I 0
                                                                     35        0.1456
                                   Four flange angles, I 0
                                      2
                                    Ay   4(6.94)(23.17) 2         14,900      62.0184
                                   Two cover plates:
                                    Ay   2(7.0)(24.50) 2           8,400      34.9634
                                      2
                                   I of gross section             26,791      111.5123
                                                                               4.12485
                                                 2
                                                                    991
                                   Deduct 2(0.87)(23.88) for excess area  ______  _________
                                   I of net section               25,800      107.387
                            5. Establish the allowable bending stress
                                                                                  0.5
                            Use the  Specification. Thus  h/t w   (48.5 – 8)/0.375 < 24,000/(22,000) ;    22,000
                            lb/sq.in. (151,690.0 kPa). Also,  M   fI/c    22(25,800)/[24.75(12)]    1911 ft·kips
                            (2591.3 kN·m).
                            6. Calculate the horizontal shear flow to be resisted
                                                                              3
                                                                                       3
                            Here Q of flange   13.88(23.17) + 7.0(24.50) – 0.87(23.88)   472 in (7736.1 cm ); q
                            VQ/I   180,000(472)/25,800   3290 lb/lin in. (576,167.2 N/m).
                              From a previous calculation procedure,  R ds   18,040 lb (80,241.9 N);  R b
                            42,440(0.375)   15,900 lb (70,723.2 N); s   15,900/3290   4.8 in. (121.92 mm), where
                                                                     3
                            s   allowable rivet spacing, in. (mm). Therefore, use a 4 /4-in. (120.65-mm) rivet pitch.
                            This satisfies the requirements of the Specification.
                              Note: To determine the allowable rivet spacing, divide the horizontal shear flow into
                            the rivet capacity.
                            DESIGN OF A WELDED PLATE GIRDER

                            A plate girder of welded construction is to support the loads shown in Fig. 8a. The dis-
                            tributed load will be applied to the top flange, thereby offering continuous lateral support.
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