Page 121 - Handbook of Civil Engineering Calculations, Second Edition
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1.104           STRUCTURAL STEEL ENGINEERING AND DESIGN

                                                           Calculation Procedure:

                                                           1. Record the properties of the
                                                           individual channel
                                                           Since x and y are axes of symmetry, they are
                                                           the principal centroidal axes. However, it is
                                                           not readily apparent which of these is the mi-
                                                           nor axis, and so it is necessary to calculate
                                                           both r x and r y . The symbol r, without a sub-
                                                           script, is used to denote the minimum radius
                                                           of gyration, in inches (centimeters).
                                                              Using the AISC Manual, we see that the
                                                           channel properties are  A   11.70 sq.in.
                                                           (75.488 cm ); h   0.78 in. (19.812 mm); r 1
                                                                    2
                                                           5.44 in. (138.176 mm); r 2   0.89 in. (22.606
                                                           mm).
                                                           2. Evaluate the minimum radius
                                                           of gyration of the built-up
                           FIGURE 11. Built-up column.
                                                           section; determine the
                                                           slenderness ratio
                                                                                          2
                                                           Thus, r x   5.44 in. (138.176 mm); r y   (r 2 +
                                                               2 0.5
                                                           5.78 )  > 5.78 in. (146.812 mm); therefore,
                                                           r   5.44 in. (138.176 mm);  KL/r
                                                           22(12)/5.44   48.5.
                            3. Determine the allowable stress in the column
                            Enter the Manual slenderness-ratio allowable-stress table with a slenderness ratio of 48.5
                            to obtain the allowable stress f   18.48 kips/sq.in. (127.420 MPa). Then, the column ca-
                            pacity   P   Af   2(11.70)(18.48)   432 kips (1921.5 kN).




                            CAPACITY OF A DOUBLE-ANGLE
                            STAR STRUT

                            A star strut is composed of two 5   5   /8 in. (127.0   127.0   9.53 mm) angles inter-
                                                         3
                            mittently connected by  /8-in. (9.53-mm) batten plates in both directions. Determine the
                                             3
                            capacity of the member for an effective length of 12 ft (3.7 m).

                            Calculation Procedure:

                            1. Identify the minor axis
                            Refer to Fig. 12a. Since p and q are axes of symmetry, they are the principal axes; p is
                            manifestly the minor axis because the area lies closer to p than q.
                                        2
                            2. Determine r v
                            Refer to Fig. 12b, where v is the major and z the minor axis of the angle section. Apply
                                                                                      2
                                                                                         2
                                            2
                                                                                 2
                                                                          2
                                    2
                                                                              2
                            I x    I x
 cos 	 + I y
 sin 	 – P x
y
 sin 2	, and set P vz   0 to get r y   r v cos 	 + r x sin 	;
                                       2
                                    2
                                            2
                                               2
                            therefore, r y sec 	 – r x tan 	. For an equal-leg angle, 	   45°, and this equation reduces
                                      2
                              2
                                   2
                            to r v   2r y – r z .
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