Page 230 - Handbook of Civil Engineering Calculations, Second Edition
P. 230

REINFORCED CONCRETE                  2.15






































                               FIGURE 8



                              3. Compute the shearing stress associated with the assumed
                              beam size
                                                            1
                              From the Code for an interior span, V u   /2w u L
  /2(390)(16)   3120 lb (13,877.8 N);
                                                                    1
                              d   6   1   5 in. (127 mm); v u   3120/[12(5)]   52 lb/sq.in. (358.54 kPa); v c   93
                              lb/sq.in. (641.2 kPa). This is acceptable.
                              4. Compute the two critical moments
                              Apply the appropriate moment equations. Compare the computed moments with the mo-
                              ment capacity of the assumed beam size to ascertain whether the size is adequate. Thus,
                                                        2
                                           2
                              M u,neg   ( /11/w u L
   ( /11)(390)(16) (12)   108,900 in.·lb (12,305.5 N·m), where the value
                                     1
                                               1
                                                                        2
                              12 converts the dimension to inches. Then M u,pos   /16w u L
   74,900 in.·lb (8462.2 N·m).
                                                                  1
                              By Eq. 10, q max   0.6375(0.85)(87/137)    0.344. By Eq. 6,  M u,allow   0.90(12)
                                2
                              (5) (3000)(0.344)(0.797)   222,000 in.·lb (25,081.5 N·m). This is acceptable. The slab
                              thickness will therefore be made 6 in. (152.4 mm).
                              5. Compute the area of reinforcement associated with each
                              critical moment
                              By Eq. 7,  bdf c   12(5)(2.55)    153.0 kips (680.54 kN); then 2bf c M u,neg /
                                                                      2
                              2(12)(2.55)(108.9)/0.90    7405 kips (146,505.7 kN );  A s,neg   [153.0    (153.0
                                                                                           2
                                                          2
                                                                                          2
                                                          2
                                  0.5
                              7405) ]/50   0.530 sq.in. (3.4196 cm ). Similarly, A s,pos   0.353 sq.in. (2.278 cm ).
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