Page 129 - Handbook of Electrical Engineering
P. 129

INDUCTION MOTORS     111

              The shunt components at the air gap are combined in parallel as:-

                                                         115.0 × j17.0
                                               R c jX m
                                       Z mc =          =
                                              R c + jX m  115.0 + j17.0
                                           = 2.4593 + j16.6365 ohms

              The total air-gap impedance Z m22 is:-

                                   Z mc Z 22  (2.4593 + j16.6365) × (6.6747 + j0.8122)
                           Z m22 =         =
                                  Z mc + Z 22  2.4593 + j16.6365 + 6.6747 + j0.8122
                                           = 5.1534 + j2.5313 ohms

              The total motor impedance Z mot is:-

                        Z mot = R 1 + jX 1 + Z m22 = 0.179 + j0.438 + 5.1534 + j2.5313
                            = 5.3324 + j2.9693 ohms, which has a magnitude of 6.1033 ohms.

              The stator current per phase I 1 is:-


                                  V p     239.6 + j0.0
                            I 1 =     =                 = 34.2982 − j19.0987 amps,
                                 Z mot  5.3324 + j2.9693
              which has a magnitude of 39.257 amps.
              The air-gap voltage V m is:-

                      V m = V p − I 1 Z 1 = (239.6 + j0.0) − (34.2982 − j19.0987)(0.179 + j0.438)

                         = 225.096 − j11.604 volts, which has a magnitude of 225.395 volts.

              The rotor current per phase I 2 is:-

                                           225.06 − j11.604
                                      V m
                                 I 2 =   =                 = 33.0235 − j5.7569 amps,
                                     Z 22  6.6747 + j0.8122
                          R c + jX m = 115.0 + j17.0

              which has a magnitude of 33.5215 amps.
              The output power P out is:-

                                        2
                            P out = 3 × I 2 × R out = 3 × 1123.691 × 6.5273 = 22.004 kW
              The magnetising current per phase I m is:-

                                          225.06 − j11.604
                                   V m
                             I m =     =                 = 0.6826 − j13.241 amps
                                  jX m         j17.0
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