Page 131 - Handbook of Electrical Engineering
P. 131

INDUCTION MOTORS     113

              The shunt components at the air gap are combined in parallel as:-

                                             115.0 × j17.0
                                   R c jX m
                           Z mc =          =              = 2.4593 + j16.6365 ohms
                                  R c + jX m  115.0 + j17.0
              The total air-gap impedance Z m22 is:-


                                           Z mc Z 22
                                   Z m22 =          = 0.2437 + j0.3288 ohms
                                          Z mc + Z 22
              The total motor impedance Z mot is:-

                                Z mot = R 1 + jX 1 + Z m22 = 0.4227 + j0.7668 ohms

              The stator current per phase I 1 is:-

                                           V p
                                      I 1 =    = 132.124 − j239.64 amps,
                                           Z mot
              which has a magnitude of 273.65 amps, which is 6.97 times the full-load value.
              The air-gap voltage V m is:-


                       V m = V p − I 1 Z 1
                          = 110.988 − j14.9748 volts, which has a magnitude of 111.994 volts.
              The rotor current per phase I 2 is:-

                                       110.988 − j14.9748
                                 V m
                            I 2 =    =                   = 132.039 − j232.98 amps,
                                 Z 22    0.253 + j0.333
              which has a magnitude of 267.795 amps.
              The output power P out is zero.
              The total shunt current I o at the air gap is:-

                                            V m
                                   I m =           = 0.0842 − j 6.6589 amps
                                          R c jX m
                                         R c + jX m

              The input kVA S in is:-
                                  ∗
                             3 × I 1 × V p
                        S in =
                                1000
                           = 94.971 + j 172.253 kVA, which has a magnitude of 196.699 kVA.

              Hence the input active power P in in kW and input reactive power Q in in kVAr are:-

                                   P in1 = 94.971 kW and Q in1 = 172.253 kVAr
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