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                                                       Therefore the permissible rise in  temperature in a stalled
                                                       condition will be as follows:
                                                       8 for bars in cold conditions  = 450 - 40 = 410°C
                                                       8 for bars in hot conditions   = 450 - 150 = 300°C
                                                       8 for rings in cold conditions =  100 - 40 = 60°C
                                                       8 for rings in hot conditions  =  100 - 70 = 30°C
        and    = J,,  = current density during start in A/cmZ and
            Am
                                                       2.8.2  Plotting thermal withstand characteristics
                                                            of the motor

         where                                         Calculate the thermal  withstand  times tSte's under cold
        k  =  material constant for the metal;         and hot  conditions  and also at different Ist, say 200%,
            (i) for aluminium = 0.016                  300% and  400%  etc.  of  I,  as  shown  below.  After
            (ii) for copper = 0.0065                   determining the  corresponding  safe thermal  withstand
            (iii) for brass = 0.0276                   times, according to the above formula, draw the graph
         :.   ts1t = - 0. -                            (Figure 2.16), Ist vs tSt:
                       I
                1
                     o,oo65  (for copper windings)
                  '
               J;:
         Note 2  Since no system can be heat adiabatic in practice there is   Stalled  current late Thermal withstand time, f,,,  in seconds
         a certain amount of heat dissipation from the impregnated windings
         to the stator core and housing. This heat dissipation  is considered   as % of I,
         as 159 of the total heat generated as in IEC 60079-7.
                                                               200
         :.  actual H, = 85% of  what has been calculated  above   3 00
                         O                                     400
         and   t,,,  =                                         5 00
                   Ji x 0.0065 x 0.85                          600
         or    f\tl  =   e   seconds(s)         (2.12)
                   Jf x 0.00552                                                      Iste
                                                       and for  J,, (for A windings) =
                                                                              . (Area of windingdtum) .Z,
         Application
         For safe stall conditions t,,e should be less than the thermal   Note  J,,  is a design parameter and more details may be obtained
                                                       from the motor manufacturer.
         withstand time of the motor under locked or short-circuit
         condition.
                                                       Example 2.4
          (i)  8 is called  the permissible  rise  in temperature in   A  250  kW  motor  has a  cold thermal  withstand  time  of  30
             the stalled condition.                    seconds and a hot thermal withstand time of 25 seconds. If
         (ii)  For  class  B  insulation,  the  maximum  limiting   the  starting time  is  7 seconds, determine the  consecutive
                                                       cold or hot starts that the motor will be able to sustain safely.
             temperature is 185°C and for class F 210°C (short-
                                                                                   30
             time permissible temperature). The permissible rise   Number of consecutive cold starts  = - = 4.3
             in temperature in class B is 80°C above an ambient                    7
             of 40°C.                                  i.e. 4 starts
                                                                                   25
             :.   8 = 185 - (40 + 80)                  and        number of  hot starts  = - 3.6
                                                                                     =
                                                                                   7
                  = 65°C for hot conditions            i.e. 3 starts
             and  8= 185 -40                           The period after which this can be repeated will depend upon
                                                       the heating curve and the thermal time constant of the motor,
                  = 145°C for cold conditions          i.e. the time the motor will take to reach thermal equilibrium
                                                       after repeated starts (See Chapter 3).
         (b) For the rotor
                                                       Example 2.5
         To ascertain  whether the stator or the rotor  would  fail   A centrifugal compressor driven through V-belts at a speed
         first  during  a  stalled  condition,  the  thermal  withstand   of  4500 r.p.m.  having the torque curve as shown in Figure
         time of  the rotor  should also be determined separately   2.18 and a moment of inertia M@  of  2.50 kgm'  employs a
         for the rotor bars and the end rings. The lowest values   squirrel cage motor with the following parameters:
         for the stator or the rotor will be the safe stall time for   kW = 350
         the  entire  motor.  The  limiting  temperatures  in  rotor   N, = 1485 r.p.m.
         components may be considered as follows:
                                                        speed-torque  characteristic as in Figure 2.18
           Limiting temperature for bars   450°C        GD; = 30 kgm'
           Limiting temperature for rings   100°C
           Operating temperature for bars   150°C       Safe stall time   hot - 30 S.
           Operating temperature for rings   70°C                    Cold - 40 S.
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