Page 22 - Instrumentation Reference Book 3E
P. 22

Basic principles of  flow measurement  7

              Discharge coefficient                   when well  away from their  critical temperatures
                                                      and  pressures)  then  the  gas  obeys  several very
                     actual mass rate of  flow
                C=                                    important gas laws. These laws will now be stated.
                    theoretical mass rate of  flow
            or if the conditions of temperature,  density, etc.,   1.2.5.1  DTJ gases
            are the same at both sections it may be written in   (a) Boyle’s law  This  states that  the volume of
            terms of volume.
                                                      any given  mass of gas will  be  inversely propor-
                c=   actual volume flowing            tional to its absolute pressure provided tempera-
                    theoretical volume flowing        ture remains constant. Thus, if a certain mass of
                                                      gas occupies a volume vo at an absolute pressure
            It  is possible to determine  C experimentally by   po and a volume 1’1  at an absolute pressurep then
            actual tests. It is a function  of  pipe size, type of
            pressure tappings, and the Reynolds number.
              Equation (1.21) is modified and becomes                                  (1.27)

                                              (1.24)   (b) Charles’s law  This states that if  the volume
                                                      of a given mass of gas occupies a volume VI at a
            This is true for flow systems where the Reynolds   temperature  TO Kelvin,  then  its  volume  v  at  T
            number is above a certain value (20,000 or above   Kelvin is given by
            for orifice plates). For lower Reynolds numbers   vllT0 = v1T   or   v = VI . TIT,   (1.28)
            and for very small or rough pipes the basic coeffi-
            cient is multiplied by a correction factor 2 whose
            value  depends  on  the  area  ratio,  the  Reynolds   (c) The ideal gas law  In the general case p, v, and
            number, and the size and roughness of the pipe.   T change. Suppose a mass of  gas at pressure po
            Values  for both  C and  Z  are  listed with  other   and temperature  TO Kelvin has a volume vo  and
            relevant data in BS  1042 Part  1 1964.   the mass of gas at pressure p  and temperature  T
              We can use differential pressure to measure flow.   has a volume v, and that the change from the first
              Here’s a practical example:             set of  conditions to the second set of conditions
                                                      takes place in two stages.
                Internal diameter of                   (a) Change the pressure from po  to p  at a con-
                  upstream pipe     D mm              stant  temperature.  Let  the  new  volume  be  VI.
                Orifice or throat                     From Boyle’s law:
                  diameter          dmm
                Pressure differential                    PO.  vo =p. VI   or   VI = vo .po/p
                  produced          hinm water gauge   (b) Change  the  temperature from  TO to  T at
                Density of fluid at                   constant pressure. From Charles’s law:
                  upstream  tapping   p kglm’
                Absolute pressure at                     VllTo = dT
                  upstream  tapping   p  bar          Hence, equating the two values of v1

            Then introducing the discharge coefficient C, the   vo .palp = v . TOIT
            correction factor and the numerical constant, the   PO. vo/To =pvlT = constant   (1.29)
            equation for quantity rate of flow Qm31h becomes
                                                      If the quantity of gas considered is 1 mole, i.e., the
                                    r
                                                      quantity  of  gas that  contains as many molecules
                                              (1.25)   as there are atoms in 0.012 kg of  carbon-12. this
                                                      constant is represented by R, the gas constant, and
            and the weight or mass rate of the flow W kglh is   equation (1  29) becomes:
            given by
                                                         PV= Ro. T
                W=0.01252C.Z.E.d2fi           (1 26)
                                                      where Ro = 8.314 JlMol K andp is in N/m2 and Y
                                                      is in m3.
            1.2.5  Modification of flow equations to apply to   Adiabatic  expansion  When  a  gas  is  flowing
            gases
                                                      through a primary element the change in pressure
            Gases are compressible, while liquids, mostly, are   takes place too rapidly for the gas to absorb heat
            not.  If  the  gas  under  consideration  can  be   from its surroundings. When it expands owing to
            regarded  as  an  ideal  gas  (most  gases  are  ideal   the reduction in pressure it does work, so that if it
   17   18   19   20   21   22   23   24   25   26   27